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Find the solution of the given initial value problem. y" + 4y = sint + uz(t)sin(t – a), y(0) = 0, y' (0) = 0 1 1 y(t) = sint +÷sin2t -juz(1)sint lUz(t)sin2t 1 y(t) = sin2t – sint – uz(1)sint – uz(t)sin2t 1 1 1 ()sin2t y(1) = =sint – sin21 – u,()sint – u-()sin2t '일이 1 y(t) = -sint 6. 1 1 1 y(t) = sint –-sin2t 1 »() = sint -sin2t - . 1 ÷sin2t 1 Uz(t)sin2t 3

Find the solution of the given initial value problem. y" + 4y = sint + uz(t)sin(t – a), y(0) = 0, y' (0) = 0 1 1 y(t) = sint +÷sin2t -juz(1)sint lUz(t)sin2t 1 y(t) = sin2t – sint – uz(1)sint – uz(t)sin2t 1 1 1 ()sin2t y(1) = =sint – sin21 – u,()sint – u-()sin2t '일이 1 y(t) = -sint 6. 1 1 1 y(t) = sint –-sin2t 1 »() = sint -sin2t - . 1 ÷sin2t 1 Uz(t)sin2t 3

Advanced Engineering Mathematics
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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Find the solution of the given initial value problem. y" + 4y = sint + U„(t)sin(t – n), y(0) = 0, y' (0) = 0 1 1 1 1 y(t) = sint + sin2 U(1)sint – u, (t)sin2t 34 3 1 1 1 1 y(t) = sin2t – sint - u, (t)sint – t(t)sin2t 3 3 1 1 1 1 Y0) = sint - sin21 –()sint – ,()sin2t y(t): 3 (1)sin2t 1 1 y() = sint – sin21 3 1 1 1 y(t) 3 =-sint sin2t - Zun(t)sin2t
Transcribed Image Text:Find the solution of the given initial value problem. y" + 4y = sint + U„(t)sin(t – n), y(0) = 0, y' (0) = 0 1 1 1 1 y(t) = sint + sin2 U(1)sint – u, (t)sin2t 34 3 1 1 1 1 y(t) = sin2t – sint - u, (t)sint – t(t)sin2t 3 3 1 1 1 1 Y0) = sint - sin21 –()sint – ,()sin2t y(t): 3 (1)sin2t 1 1 y() = sint – sin21 3 1 1 1 y(t) 3 =-sint sin2t - Zun(t)sin2t
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