Find the solution of the given initial value problem. y" + 3y' + 2y = u2(t), y(0) = 4, y' (0) = u2(t) y(t) = "21 – 2e1-2) + e-2(1-2)| + 12e + 8e¬2! 8e-21 ·e-2«-2)] + 12e¬t + 2 y(t) = "2 [1 – 2e-0-2) + e-2(-2)| + 12e¬ – 8e-21 u2(t) y() = "3 1 – [1 – 2e--2) + e2(1-2)] + 4e¬' – 4e-2! 2 y(t) u2(t) y(t) = "21 + 2e-(-2) + e-2(-2)| + 12e¬ – 8e-21 U2 (t) y(t) = "21 – 2e1-2) + e-2(1-2)| + 4e – 16e-2" + e-2-2)] + 4e¬ – 16e¯
Find the solution of the given initial value problem. y" + 3y' + 2y = u2(t), y(0) = 4, y' (0) = u2(t) y(t) = "21 – 2e1-2) + e-2(1-2)| + 12e + 8e¬2! 8e-21 ·e-2«-2)] + 12e¬t + 2 y(t) = "2 [1 – 2e-0-2) + e-2(-2)| + 12e¬ – 8e-21 u2(t) y() = "3 1 – [1 – 2e--2) + e2(1-2)] + 4e¬' – 4e-2! 2 y(t) u2(t) y(t) = "21 + 2e-(-2) + e-2(-2)| + 12e¬ – 8e-21 U2 (t) y(t) = "21 – 2e1-2) + e-2(1-2)| + 4e – 16e-2" + e-2-2)] + 4e¬ – 16e¯
Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter4: Polynomial And Rational Functions
Section: Chapter Questions
Problem 5T
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![Find the solution of the given initial value problem.
y" + 3y' + 2y = u2(t), y(0) = 4, y' (0) = 4
u2 (t)
y(t)
[1 – 2e--2) + e-2(1-2)] + 12e + 8e-2
2
U2 (t)
y(t):
- 2e-(-2) + e-2(1–2)] + 12e- – 8e-2
y(t):
u2 (t)
[1 – 2e-(-2) + e-2(1–2)] + 4e- – 4e-2!
u2 (t)
y(t) = "[1 + 2e-(-2) + e-2(-2)] + 12e¬ – 8e-24
2
u2(t)
y(t) = "2 1 – 2e¬(-2) + e-2(-2)| + 4e - 16e-21
+e 20-2)] + 4e
2](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F77cac1a6-5ad9-4f72-bdd9-21a202e53df4%2Fc80f6c2c-e3da-4e12-985a-54ca37de6964%2Flabseuu_processed.png&w=3840&q=75)
Transcribed Image Text:Find the solution of the given initial value problem.
y" + 3y' + 2y = u2(t), y(0) = 4, y' (0) = 4
u2 (t)
y(t)
[1 – 2e--2) + e-2(1-2)] + 12e + 8e-2
2
U2 (t)
y(t):
- 2e-(-2) + e-2(1–2)] + 12e- – 8e-2
y(t):
u2 (t)
[1 – 2e-(-2) + e-2(1–2)] + 4e- – 4e-2!
u2 (t)
y(t) = "[1 + 2e-(-2) + e-2(-2)] + 12e¬ – 8e-24
2
u2(t)
y(t) = "2 1 – 2e¬(-2) + e-2(-2)| + 4e - 16e-21
+e 20-2)] + 4e
2
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