Find the solution of the differential equation у" — 16у 3D 2е\x y = C,eªx C2e¬4x + +xe4x а. 4 b. y = C¸e4x C2e¬4x xe4x 4 %3D с. y = C,e4* C2e¯4x + xe4x 2 d. 1 y = Ce4x C2e¬4X – xe4x 2

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A: Now we solve this below

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A: Hello, thanks for your question but according to our policy I am doing the very first question.…

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