Find the solution of the differential equation (t² + x²)dt + (2tx − x) dx = 0. a. 2t³ - 6tx² – 3x² = c b. 2t³ + 6tx²-3x² = c c. 2t³ +6tx² + 3x² = = C d. t3+3tx² + 3x² = e. t³-3tx²-3x² = c =C
Find the solution of the differential equation (t² + x²)dt + (2tx − x) dx = 0. a. 2t³ - 6tx² – 3x² = c b. 2t³ + 6tx²-3x² = c c. 2t³ +6tx² + 3x² = = C d. t3+3tx² + 3x² = e. t³-3tx²-3x² = c =C
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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E13
Transcribed Image Text:Find the solution of the differential equation (t² + x²)dt + (2tx − x) dx = 0.
a. 2t³6tx²-3x² = c
b. 2t³ + 6tx² – 3x² = = C
c. 2t³ + 6tx² + 3x² = c
t³ + 3tx² + 3x² =
d.
= C
e.
t³-3tx²-3x²
= C
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