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Find the solution of dr = b cos 0 dr + r sin 0 de. A. rb = cb (1 +b cos 0) B. rb = cb (1 -b cos 0) C. r=c (1- b cos 0) Answer: Evaluate ((24x5 - 4x³ + 12x² )dx. А. 4xл6 - хл4 + 4х^3 + с B. 4x^6 + x^4 + 4x^3 + c С. 4хл6 - хл4- 4х^3 + с Answer:

Find the solution of dr = b cos 0 dr + r sin 0 de. A. rb = cb (1 +b cos 0) B. rb = cb (1 -b cos 0) C. r=c (1- b cos 0) Answer: Evaluate ((24x5 - 4x³ + 12x² )dx. А. 4xл6 - хл4 + 4х^3 + с B. 4x^6 + x^4 + 4x^3 + c С. 4хл6 - хл4- 4х^3 + с Answer:

Advanced Engineering Mathematics
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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Find the solution of dr = b cos 0 dr + r sin 0 de. A. rb = cb (1 + b cos 0) B. rb = cb (1-b cos 0) C. r= c (1-b cos 0) Answer: Evaluate (24x5 - 4x³ + 12x² )dx. А. 4x^6 - хл4 + 4х^3 + с В. 4хл6 + хл4 + 4хл3 + с С. 4хл6 - хл4- 4х^3 + с Answer:
Transcribed Image Text:Find the solution of dr = b cos 0 dr + r sin 0 de. A. rb = cb (1 + b cos 0) B. rb = cb (1-b cos 0) C. r= c (1-b cos 0) Answer: Evaluate (24x5 - 4x³ + 12x² )dx. А. 4x^6 - хл4 + 4х^3 + с В. 4хл6 + хл4 + 4хл3 + с С. 4хл6 - хл4- 4х^3 + с Answer:
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