Find the Solution (1+12) ds + 21[st² – 3 (1+12) ²jdt = 0; when t = 0, s = 2. t = (1 – s²)[2-e- A s = (1 – 12)[2-e- © 1 = (1 + s2)[3-e*] s = (1 + t?)[3–-e-

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