Find the smallest possible force that the woman should pull to cause the crate to slide. Coefficientof static friction is 0.20. PROBLEM 2: A woman is trying to move the crate of weight W = 12 kN by pulling on the rope at theangle q to the horizontal.w=12 kNH;=0.20a. Find the smallest possible force that the woman should pull to cause the crate to slide. Coefficientof static friction is 0.20.b. Determine the angle q.c. Determine the horizontal frictional force acting at the bottom of the carte.

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Description: Find the smallest possible force that the woman should pull to cause the crate to slide. Coefficientof static friction is 0.20. PROBLEM 2: A woman is trying to move the crate of weight W = 12 kN by pulling on the rope at theangle q to the horizontal.

Given data: Weight of the Crate is, W= 12 kN Coefficient of static friction is, μs=0.20 Formula…

Answered: Find the smallest possible force that…

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Find the smallest possible force that the woman should pull to cause the crate to slide. Coefficient of static friction is 0.20.

Glencoe Physics: Principles and Problems, Student Edition

1st Edition

ISBN:9780078807213

Author:Paul W. Zitzewitz

Publisher:Paul W. Zitzewitz

Chapter5: Displacement And Force In Two Dimensions

Section: Chapter Questions

Problem 71A

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Newton’s laws of motion describe the relationship between the motion of an object and forces acting on it. Newton’s law of motion has two types as follows:

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Find the smallest possible force that the woman should pull to cause the crate to slide. Coefficient
of static friction is 0.20.

PROBLEM 2: A woman is trying to move the crate of weight W = 12 kN by pulling on the rope at the
angle q to the horizontal.
w=12 kN
H;=0.20
a. Find the smallest possible force that the woman should pull to cause the crate to slide. Coefficient
of static friction is 0.20.
b. Determine the angle q.
c. Determine the horizontal frictional force acting at the bottom of the carte.

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