Find the slope of the curve at the given point P and an equation of the tangent line at P. y=x²+5x, P(4,36) 1 x 1 OA. The slope of the curve is 20 at P. The line y = 20*5 is tangent at P. OB. The slope of the curve is-39 at P. The line y = -39x-80 is tangent at P. Oc. The slope of the curve is 13 at P. The line y = 13x-16 is tangent at P. 4 4x 8 OD. The slope of the curve is - 25 at P. The line y = -25*5 is tangent at P.