Find the slope of the curve at the given point P and an equation of the tangent line at P. y=x²+5x, P(4,36) 1 x 1 OA. The slope of the curve is 20 at P. The line y = 20*5 is tangent at P. OB. The slope of the curve is-39 at P. The line y = -39x-80 is tangent at P. Oc. The slope of the curve is 13 at P. The line y = 13x-16 is tangent at P. 4 4x 8 OD. The slope of the curve is - 25 at P. The line y = -25*5 is tangent at P.

Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Find the slope of the curve at the given point P and an equation of the tangent line at P.
y=x²+5x, P(4,36)
1
X
1
OA. The slope of the curve is
20
at P. The line y = 20*5 is tangent at P.
OB. The slope of the curve is-39 at P. The line y = -39x-80 is tangent at P.
Oc. The slope of the curve is 13 at P. The line y = 13x-16 is tangent at P.
4
4x 8
OD. The slope of the curve is -
25
at P. The line y = -25*5 is tangent at P.
Transcribed Image Text:Find the slope of the curve at the given point P and an equation of the tangent line at P. y=x²+5x, P(4,36) 1 X 1 OA. The slope of the curve is 20 at P. The line y = 20*5 is tangent at P. OB. The slope of the curve is-39 at P. The line y = -39x-80 is tangent at P. Oc. The slope of the curve is 13 at P. The line y = 13x-16 is tangent at P. 4 4x 8 OD. The slope of the curve is - 25 at P. The line y = -25*5 is tangent at P.
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