Find the slope and y-intercept of the line through the point (5,9) that cuts off the le slope = %3D

Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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**Mathematics Problem: Finding Slope and Y-Intercept**

*Problem Statement:*

Find the slope and y-intercept of the line through the point (5,9) that cuts off the least area from the first quadrant.

*Fill in the following fields:*

- **Slope:** _______________
- **Y-Intercept:** _______________

**Explanation:**

To tackle this problem, you'll need to use your knowledge of geometry and algebra involving lines on the coordinate plane. Let's break down the steps:

1. **Determine the Slope (m):**
   The slope of a line that passes through two points \((x_1, y_1)\) and \((x_2, y_2)\) is given by
   \[ m = \frac{y_2 - y_1}{x_2 - x_1} \]
   In this case, we know one point \((5, 9)\) and we need to find the slope that minimizes the area cut off in the first quadrant.

2. **Find the Y-Intercept (b):**
   Once the slope is determined, use the point \((5, 9)\) to find the y-intercept. The equation of the line in slope-intercept form is:
   \[ y = mx + b \]
   Substitute \((5, 9)\) and solve for \(b\).

3. **Minimize the Area:**
   To minimize the area of the triangle formed in the first quadrant, consider how the slope affects the x and y intercepts.

Following these steps will guide you towards the solution. Once you find the slope and y-intercept, input the values into the provided fields.

- **Slope:** _______________
- **Y-Intercept:** _______________

Feel free to reach out to your instructor or refer to geometry resources if you need additional assistance with these calculations.
Transcribed Image Text:**Mathematics Problem: Finding Slope and Y-Intercept** *Problem Statement:* Find the slope and y-intercept of the line through the point (5,9) that cuts off the least area from the first quadrant. *Fill in the following fields:* - **Slope:** _______________ - **Y-Intercept:** _______________ **Explanation:** To tackle this problem, you'll need to use your knowledge of geometry and algebra involving lines on the coordinate plane. Let's break down the steps: 1. **Determine the Slope (m):** The slope of a line that passes through two points \((x_1, y_1)\) and \((x_2, y_2)\) is given by \[ m = \frac{y_2 - y_1}{x_2 - x_1} \] In this case, we know one point \((5, 9)\) and we need to find the slope that minimizes the area cut off in the first quadrant. 2. **Find the Y-Intercept (b):** Once the slope is determined, use the point \((5, 9)\) to find the y-intercept. The equation of the line in slope-intercept form is: \[ y = mx + b \] Substitute \((5, 9)\) and solve for \(b\). 3. **Minimize the Area:** To minimize the area of the triangle formed in the first quadrant, consider how the slope affects the x and y intercepts. Following these steps will guide you towards the solution. Once you find the slope and y-intercept, input the values into the provided fields. - **Slope:** _______________ - **Y-Intercept:** _______________ Feel free to reach out to your instructor or refer to geometry resources if you need additional assistance with these calculations.
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