Find: The shortest distance from the point (2, 1, 3) to the plane x+y+z= 1. = The shortest distance between the line parametrized by (x, y, z) (4-t, 3+ t, −1+t) and the line parametrized by (x, y, z) = (4+ s, −1 – 2s, 1 — s). -

Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
Question
Find:
The shortest distance from the point (2, 1, 3) to the plane x+y+z=
1.
=
The shortest distance between the line parametrized by (x, y, z)
(4-t, 3+ t, −1+t) and the line parametrized by (x, y, z)
=
(4+
s, −1 – 2s, 1 — s).
-
Transcribed Image Text:Find: The shortest distance from the point (2, 1, 3) to the plane x+y+z= 1. = The shortest distance between the line parametrized by (x, y, z) (4-t, 3+ t, −1+t) and the line parametrized by (x, y, z) = (4+ s, −1 – 2s, 1 — s). -
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