Find the shear forces.(a)M = 3.89 KNM((6)M= 3.36kN3.36 KNि(c)M=-3.36 km (AAW=7.3 kN/m#AImW = 14.6 kN/m24!!"2mTITBM = 3.36 kNmw=6.99kN/m2m1.99m BBM= 3.36 kNmM = 336kN m

Answer (a) Let us first draw the free body diagram for figure 'a' and calculate the reactions at…

Answered: Find the shear forces.

Engineering

Civil Engineering

Find the shear forces.

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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Concept explainers

System of Forces

A force is an external influence or agent that changes the state of a system. According to Newton's second law, the force applied to a body is proportional to the change in momentum of a body. Hence, whenever a force is applied to a body, its momentum changes. If the body is at rest, under the action of force, its state of rest changes to motion. In other words, the magnitude of the momentum of the body changes from zero to a measurable value. Similarly, if the body possesses some initial velocity, it has some associated momentum, the effect of force can cause the body to halt or come to rest, that is, the momentum reduces to zero.

Question

Find the shear forces.
(a)
M = 3.89 KNM
(
(6)
M= 3.36kN
3.36 KN
ि
(c)
M=-3.36 km (
A
A
W=7.3 kN/m
#
A
Im
W = 14.6 kN/m
24!!"
2m
TIT
B
M = 3.36 kNm
w=6.99kN/m
2m
1.99m B
B
M= 3.36 kNm
M = 336kN m

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