Find the second derivative of the function. 20 (2-0) 20 dr 2 O A. do 2 1 B. do? O OC. do 1 OD. do?

Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Find the second derivative of the function:

\[
r = \left(\frac{1 + 20}{20}\right)(2 - \theta)
\]

Options:

- A. \( \frac{d^2r}{d\theta^2} = \frac{2}{\theta^3} \)

- B. \( \frac{d^2r}{d\theta^2} = \frac{-2}{\theta^3 - 1} \)

- C. \( \frac{d^2r}{d\theta^2} = \frac{1}{\theta - 1} = 0 \)

- D. \( \frac{d^2r}{d\theta^2} = \frac{1}{\theta^2 - 1} \)
Transcribed Image Text:Find the second derivative of the function: \[ r = \left(\frac{1 + 20}{20}\right)(2 - \theta) \] Options: - A. \( \frac{d^2r}{d\theta^2} = \frac{2}{\theta^3} \) - B. \( \frac{d^2r}{d\theta^2} = \frac{-2}{\theta^3 - 1} \) - C. \( \frac{d^2r}{d\theta^2} = \frac{1}{\theta - 1} = 0 \) - D. \( \frac{d^2r}{d\theta^2} = \frac{1}{\theta^2 - 1} \)
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