Find the saponification # of cod liver oil if a 1.1090 g is saponified with 25 mL of 0.5N alcoholic KOH. It required 8.6 mL of 0.5112 N HCI to titrate the endpoint. In blank determination, 18 mL of same titrant was required to titrate the alkali. Your answer If 2.1921 g of oil sample required 5.10 mL of 0.1N NAOH in the titration. What would the acid value be?

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Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
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Chapter1: Chemical Foundations
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Find the saponification # of
cod liver oil if a 1.1090 g is
saponified with 25 mL of 0.5N
alcoholic KOH. It required 8.6
mL of 0.5112N HCI to titrate
the endpoint. In blank
determination, 18 mL of same
titrant was required to titrate
the alkali.
Your answer
If 2.1921 g of oil sample
required 5.10 mL of 0.1N NaOH
in the titration. What would
the acid value be?
Your answer
Transcribed Image Text:Find the saponification # of cod liver oil if a 1.1090 g is saponified with 25 mL of 0.5N alcoholic KOH. It required 8.6 mL of 0.5112N HCI to titrate the endpoint. In blank determination, 18 mL of same titrant was required to titrate the alkali. Your answer If 2.1921 g of oil sample required 5.10 mL of 0.1N NaOH in the titration. What would the acid value be? Your answer
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