Find the RREF of [A| I], then determine whether A is invertible and, if so, find A-1. 2 -2 1 2 3 (i) A = 1 -1 -1 -2 4 5 6 (ii) A = 2 1 7 8 9 1 3 1

Q: (A + B) E M mx n A+B=B+ A A+ (B+C) = (A + B) + C A+O=A

A: As per guidelines we can solve first 3 subparts. Please repost the other parts

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A: It is given that, if a polynomial p(x) can be factored as a product of two lower degree polynomials…

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Q: (1 1 1 2 3 1 Let A = If B = (b, b2 b3) is the inverse of A 1 2 2 then which of the following is b2 ?…

A: Answer

Q: 2. Prove that if 5BA+ ACA – I = A, then A must be invertible.

A: We have a solve the problem

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Q: Find the determinate by expanding about the 1st row. 1 3-1 223 1-1 0

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Q: Use Cramer's Rule to solve for x2. xi + 2x2 +x3 = 2 3x1 – x2 - 2x3 = 7 X2 +x3 = -1

A: Here we have given one matrix and we have to find the value of x2 by using the Cremer’s rule.   Now…

Q: (c) If A and B are invertible, express [(AB)-¹]ª with A−¹ and B-¹.

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