Find the resultant Force and direction of adding the three vectors shown ### Understanding Vector Addition Using Force DiagramThe diagram shown illustrates multiple vectors, each representing a force with different magnitudes and directions. This is a common type of diagram used in physics to study the resultant force and equilibrium conditions.#### Diagram Analysis:1. **Vectors and Their Magnitudes:** - **Vector A:** Directed to the left, labeled as "4k". - **Vector B:** Directed upwards, forming a 50-degree angle with the horizontal axis, labeled as "10k". - **Vector C:** Directed downwards at an angle, labeled as "8k". Additionally, small lines labeled "2" and "3" form a right-angled triangle indicating the horizontal and vertical components of this vector.2. **Angles:** - There is an angle of 50 degrees between Vector B (10k) and the horizontal axis.3. **Vector Components:** - For Vector C: It's broken down into horizontal (2k) and vertical (3k) components. It is common to decompose a vector into components when calculating the resultant vector or when analyzing equilibrium.#### Concepts Illustrated:- **Vector Addition:** To find the resultant force vectors acting on a point, use vector addition. This can be done using graphical methods (triangle or parallelogram rule) or analytical methods (using components).- **Equilibrium:** If forces are in equilibrium, the sum of all forces will be zero. This diagram can be used to visualize and calculate whether forces are balanced and the system is in equilibrium.- **Trigonometry in Vectors:** Angles are used to resolve vectors into their horizontal and vertical components using trigonometric functions (sine and cosine).### Practical Applications:- **Engineering:** Understanding how to add and resolve forces is crucial in structural engineering, mechanical systems, and any field where force analysis is needed.- **Physics:** Fundamental in studying mechanics, particularly in statics and dynamics.### Calculation Process:To determine the resultant vector or to check for equilibrium:1. **Resolve Vector B and Vector C into their components.**2. **Sum the horizontal components** of all vectors.3. **Sum the vertical components** of all vectors.4. **Check for equilibrium** by ensuring the net horizontal and vertical components are zero.This breakdown simplifies complex vector problems into manageable calculations, making it easier to analyze forces acting on a point.

Answered: Image /qna-images/answer/b144f57d-3e3a-4d8f-9bf5-8a93ad7d8239.jpg

Answered: Find the resultant Force and direction…

Engineering

Mechanical Engineering

Find the resultant Force and direction of adding the three vectors shown

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

See similar textbooks

Similar questions

After the web meeting, submit this document on Canvas Undel ne Meeting Assignment. This is an individual submission. TAE %3D Follow the steps below to express the force F, as a vector using the format: F, = F 1. Write the position vector: TAE = 4 ft 4 ft F = 300 lb 6 ft 6 ft 2. Find the magnitude of the position vector: 6 ft TAE = F = 400 lb 3. Find the unit vector by dividing the position vector by its own magnitude: NAE = 4. Write the force vector: F1 =FinAE =
Q) A simplified model as shown in figure below of a planar robotic arm. You may assume that each segment has length 1.5 m, and the applied force is 250 N. 01 = 35 degree and 02 %3D = 03 = 20 degree. Calculate the moment that the force, F, exerts * .about the point A F B C
令回 docs.google.com/forms O Q) A simplified model as shown in figure below of a planar robotic arm. You may assume that each segment has length 1.5 m, and the applied force is 250 N. 01 = 35 degree and 02 = 03 = 20 degree. Calculate the moment that the force, F, exerts * .about the point A M = -1050 O M = -1046 M = -1055 M = -1042 O :
B. Figure 2 below shows a 400 N force, F, acting on a pipe. 4m F-400N 6m 4m Figure 2 i. Find the position vector of roA and TAB ii. Find the unit vector of OA and AB iii. Determine the component of F acting along the pipe, OA.
F1 F2 a C F3 A d F4 D Consider the following values: - F5 a = 25 m; b = 5 m; c = 25 m; d = 5 m; F1 = 4 kN; F2 = 2 kN; F3 = 5 kN; F4 = 7 kN; F5 = 3 kN; a = 30° , 0 = 60° , B = 30° 1] What is the resultant moment of the five forces acting on the rod about point A?
F1 F2 F3 A B d b F4 D F5 Consider the following values: - a = 25 m; b = 5 m; c = 25 m; d = 5 m; F1 - 6 kN; F2 - 7 kN; F3 = 8 kN; F4 - 9 kN; F5 - 10 kN; a = 30°, 0 = 45° , B = 60° 1] What is the resultant moment of the five forces acting on the rod about point A? a) - 154.8 kN.m b) 111.9 KN.m c) - 174.6 kN.m d) 162.9 kN.m e) 214.1 kN.m 0-47.1 kN.m 2] What is the resultant moment of the five forces acting on the rod about point B? | a) - 209.3 kN.m b) 215.7 kN.m c) 311.6 kN.m d) - 98.9 kN.m e) 125.4 kN.m f) - 124.2 kN.m 3] What is the resultant moment of the five forces acting on the rod about point C? a) - 204 kN.m b) 121 kN.m c) 146 kN.m d) - 279 kN.m e) 241 kN.m D- 353 kN.m 4] What is the resultant moment of the five forces acting on the rod about point D? a) – 212.7 kN.m b) 182.7 kN.m e) - 21.9 kN.m d) 36.9 kN.m e) - 27.1 kN.m ) 30.1 kN.m 5] What is the moment of the force F2 about point E? a) 100.3 kN.m b) 118.1 kN.m c) 224.6 kN.m d) 193.1 kN.m e) 151.1 kN.m ) 221.3 kN.m E.
Given three vectors A = 24i + 33j, B = 55i - 12j and C = 2i + 43j (a) Find the magnitude of each vector. (b) Write an expression for the vector difference A - C. (c) Find the magnitude and direction of the vector difference A-B. (d) In a vector diagram show yector A+B, and A - B, and also show that your diagram agrees qualitatively with your answer.
As shown, three forces, F1, F2, and F3, act at the same point on an object. (Figure 2) The point of application is the origin of a Cartesian coordinate system. F1, which has a magnitude of F₁ = 15.0 kN, is in the y-z plane and is described by an angle 1 = 33.0 degrees. F2 is in the x-z plane and is described by integer lengths of a similar right triangle; its magnitude is F2 = 17.0 kN. If the sum of the forces is equal to zero, what is the magnitude of F3? - Express your answer numerically in kilonewtons to three significant figures.
Engineering Analysis ENGR 1022. Vectors Homework #3 1. Compute the dot product for the following two vectors. A=51+3) and = 31-10) 2. Compute the cross product for the following vectors? C= 61-9) and 5 =91-4k 3. What is the force in cable AC? See diagram below. B 500 lb 4. The magnitude of torque equals force times distance. The vector form is r=7x F. F is the force vector and F is the position vector. You are pushing on a merry-go-round with a radius of 5 ft with a force of 40 lbs. What is the torque vector value? The z axis is pointing out of the sheet of paper. See diagram below. y 5. Show that vectors 7,7, and F in problem 4 are all perpendicular to each other. University of Arkans Fot S5210 Grand Avenue PO, Box 3649 Fort South, Arkama 72933-3649-475-753-7000
( FR = Value Units 2m Submit Request Answer Part B F= 380 NA F= 400 N Determine the coordinate direction angle a of the resultant force of the two forces acting on the sign Fg= 400 N /D at point A Express your answer using three significant figures. vec Pearson 10:55 A all 22.04.2021
F1 F2 F3 A b F4 D F5 Consider the following values: - a = 25 m; b 5 m; c = 25 m; d = 5 m; F1 = 4 kN; F2 = 5 kN; F3 = 6 kN; F4 = 7 kN; F5 = 8 kN; a = 30°, 0 = 60° %3D B = 30° 1] What is the resultant moment of the five forces acting on the rod about point A? a) - 75.8 kN.m b) 32.7 kN.m c) - 14.6 kN.m d) 72.9 kN.m e) 27.1 kN.m - 66.1 kN.m 2] What is the resultant moment of the five forces acting on the rod about point B? a) - 198.8 kN.m b) 212.7 kN.m c) - 121.6 kN.m d) 98.9 kN.m e) 125.4 kN.m f) -170.2 kN.m 3] What is the resultant moment of the five forces acting on the rod about point C? a) - 96.7 kN.m b) 251.1 kN.m c) - 114.6 kN.m d) 217.9 kN.m 154.1 kN.m f)-177.7 kN.m 4] What is the resultant moment of the five forces acting on the rod about point D? a) - 198 kN.m b) 127 kN.m c) – 219 kN.m d) 369 kN.m e) 151 kN.m f) - 171 kN.m Activate V 5] What is the moment of the force F2 about point E? Go to Setting
if T= 296KN a. What is the rectangular representation of force T. b. What is the moment of T about point 0 (in vector form). c. What is the moment of T about point D (in vector form). d. What is the moment of T about axis CE (in vector form). 1.8 m 2.4 m 2.4 m 3 m 1.8 m 30 B0.3 m. 2.4 m 1.5 m