Find the required sample size without making a guess for the observed value of p. A computer manufacturer wishes to estimate what proportion of their laptop computers are defective. Obtain a sample size that will ensure a margin of error of at most 3.2 percentage points for a 95% confidence interval.

Q: In a random sample of 60​ computers, the mean repair cost was​ $150 and assume that the population…

A: Given: In a random sample of 60​ computers, the mean repair cost was​ $150  the population…

Q: Suppose that your sample size is 3000 and that you wish to construct a 95% confidence interval. Your…

A: From the provided information,n = 3000Confidence level = 95%Sample standard deviation (s) = 42.3

Q: random sample of ten people, the mean driving distance to work was 23.2 miles and the standard…

A: Given  Sample mean=x̄=23.2, s=7.4,n=10

Q: Is there a difference in the average age that people get married in the US and its close neighbor,…

A: Obtain the 95% confidence interval for the mean rating. The 95% confidence interval for the mean…

Q: In a random sample of six cell​ phones, the mean full retail price was ​$482.50 and the standard…

A: Confidence interval: Since the population standard deviation is unknown and the sample size is…

Q: In a random sample of twelve ​people, the mean driving distance to work was 22.4 miles and the…

A: Given :  In a random sample of twelve people, the mean driving distance to work was 2.24 miles and…

Q: A wildlife study is designed to find the mean weight of salmon caught by an Alaskan fishing company.…

A: Given information Standard deviation σ= 2.10 Confidence interval = 0.95 Significance level(α) = 1-…

Q: Suppose you use simple random sampling to select and measure 47 dogs' weights, and find they have a…

A: Given, mean is 78 and standard deviation is 13.5. Sample number is 47. We with use one sample z…

Q: In a random sample of eleven people, the mean driving distance to work was 25.9 miles and the…

A: Given data In a random sample of eleven people, the mean driving distance to work was 25.9 miles and…

Q: Estimate the variability in such sample proportions by finding the standard error. Among 1815…

A:

Q: 3. Monthly food expenditures for families in Caloocan City average P4,500 with a standard deviation…

A: Given Monthly food expenditures for families in Caloocan city average P4,500 with a standard…

Q: A random sample of 40 college students averaged 5 hours of sleep per night. Assume a population…

A: We have given that,  Sample size (n) = 40, sample mean or average (x̄) =5 and population standard…

Q: he average weight of 20 randomly selected cars was 3500 pounds. The sample standard deviation was…

A: given data, n=20df=n-1=20-1=19x¯=3500 pounds s=315 pounds CI=0.90α=1-0.90=0.10

Q: A couple wants to rent an unfurnished apartment room in New York next month. The mean monthly rent…

A:

Q: You measure 43 randomly selected textbooks' weights, and find they have a mean weight of 33 ounces.…

A: We have to find 95% confidence interval for the true population mean textbook weight.

Q: The U.S. Census Bureau conducts a study to determine the time needed to complete the short form. The…

A: Given, Sample size n = 200 Mean x¯ = 8.2 Standard deviation σ = 2.2 96% confidence interval  α =…

Q: Claim: The mean pulse rate (in beats per minute) of adult males is equal to 68.6 bpm. For a random…

A:

Q: In a random sample of ten ​people, the mean driving distance to work was 18.1 miles and the standard…

A:

Q: stributed and use the t-distribution to find the margin of error and construct a 95% confidence…

A: df=n-1=10−1=9 The critical t-value for α=0.05 and df=9 degrees of freedom is tc​=2.262. (from t…

Q: 1. A budget head for SSS Sales Inc. would like to compare the daily travel expenses for the sales…

A: We’ll answer the first question since the exact one wasn’t specified. Please submit a new question…

Q: Find the sample size needed to estimate the percentage of adults who can wiggle their ears. Use a…

A: It is given that Margin of error E = 0.04 Confidence level = 95% The critical value of Z at 95%…

Q: Find a 95% confidence interval for the difference between full attendance students' Exam 5 score and…

A: We have given data,  Less attendance Full attendance 90 96 90 96 60 100 50 99 69   88…

Q: 5. You randomly select and weigh 30 samples of an allergy medicine. The sample standard deviation is…

A:

Q: In a random sample of 40 computers, the mean repair cost was $150.population standard deviation is…

A:

Q: An administrator in charge of undergraduate education on a large campus wanted to estimate the…

A: Introduction: The 100 (1 – α) % confidence interval for the population mean, μ, when the population…

Q: Suppose that your sample size is 3 and that you wish to construct a 95% confidence interval. Your…

A: Sample Size= 3Standard eviation=20.4Confidence of interval = 95%We have to find margin of error?

Q: In a random sample of five people, the mean driving distance to work was 22.5 miles and the standard…

A:

Q: You measure 46 textbooks' weights, and find they have a mean weight of 34 ounces. Assume the…

A: given data population sd(σ) = 14.3n = 46x¯ = 3495% ci for mean (μ) = ?

Q: A popular weight loss program claims users will lose weight each month. Linda samples 25 dieters and…

A: We have given that,  Sample mean (x̄) = 10 pounds, standard deviation (s) = 2 pounds and sample size…

Q: In a random sample of five people, the mean driving distance to work was 23.2 miles and the standard…

A: Given,sample size(n)=5sample mean(x¯)=23.2standard deviation(s)=7.7degrees of…

Q: In a random sample of eight people, the mean driving distance to work was 24.2 miles and the…

A:

Q: for a sample of 57 that has a mean of 6200 and a standard deviation of 254, calculate the 95%…

A:

Q: or a sample of 121 that has a mean of 6540 and a standard deviation of 780, calculate the 90%…

A:

Q: In a random sample of five people, the mean driving distance to work was 19.3 miles and the standard…

A: The sample size is n = 5 Sample mean = 19.3 Sample SD = 6.4 The critical value of t at (n - 1) = 4…

Q: In a random sample of 60 refrigerators, the mean repair cost was $157.08. Assume the population…

A: Given that,The sample size is  refrigerators.The sample mean is The population standard deviation is…

Q: Construct a confidence interval for a population mean.             In order to estimate the number…

A: Since the population standard deviation is unknown, t distribution can be used for the computation…

Q: To decide what personnel requirements should be enforced, a hospital manager wants to estimate the…

A:

Q: The Highway Safety Department wants to study the driving habits of individuals. A sample of 81 cars…

A: Given information Sample size (n) = 81 Sample mean x̅ = 67 mph Standard deviation (s) = 9 mph…