Find the remainder when 819054 is divided by 13.

Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
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**Problem Statement:**

Find the remainder when \(8^{19054}\) is divided by 13.

**Explanation:**

This problem involves finding the remainder of a large power when divided by a number. It can often be solved using modular arithmetic techniques such as Fermat's Little Theorem, which states that if \(p\) is a prime number and \(a\) is an integer not divisible by \(p\), then \(a^{p-1} \equiv 1 \ (\text{mod} \ p)\).

Here, since 13 is a prime number, we can apply this theorem. Specifically:

1. Verify that 13 is a prime and does not divide 8.
2. Apply Fermat's Little Theorem:
   \[
   a^{p-1} \equiv 1 \ (\text{mod} \ p)
   \]
   For \(a = 8\) and \(p = 13\):
   \[
   8^{12} \equiv 1 \ (\text{mod} \ 13)
   \]
3. Break down \(8^{19054}\) by expressing its exponent in terms of multiples of 12.

Please refer to mathematical methods such as modular arithmetic or Fermat's Little Theorem for further steps in solving such problems.
Transcribed Image Text:**Problem Statement:** Find the remainder when \(8^{19054}\) is divided by 13. **Explanation:** This problem involves finding the remainder of a large power when divided by a number. It can often be solved using modular arithmetic techniques such as Fermat's Little Theorem, which states that if \(p\) is a prime number and \(a\) is an integer not divisible by \(p\), then \(a^{p-1} \equiv 1 \ (\text{mod} \ p)\). Here, since 13 is a prime number, we can apply this theorem. Specifically: 1. Verify that 13 is a prime and does not divide 8. 2. Apply Fermat's Little Theorem: \[ a^{p-1} \equiv 1 \ (\text{mod} \ p) \] For \(a = 8\) and \(p = 13\): \[ 8^{12} \equiv 1 \ (\text{mod} \ 13) \] 3. Break down \(8^{19054}\) by expressing its exponent in terms of multiples of 12. Please refer to mathematical methods such as modular arithmetic or Fermat's Little Theorem for further steps in solving such problems.
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