Find the regression equation, letting the first variable be the predictor (x) variable. Using the listed actress/actor ages in various years, find the best predicted age of the Best Actor winner given that the age of the Best Actress winner that year is 29 years. Is the result within 5 years of the actual Best Actor winner, whose age was 38 years? Best Actress 22 42 56 O 46 35 27 34 46 29 28 38 38 46 60 30 28 53 60 39 58 Best Actor 44 51 49 58 Find the equation of the regression line. (Round the y-intercept to one decimal place as needed. Round the slope to three decimal places as needed.)

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ISBN:9781119256830
Author:Amos Gilat
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### Regression Analysis Problem

In this exercise, you are tasked with finding the regression equation using the given data. The first variable is the predictor (\(x\)) variable. The goal is to predict the age of the Best Actor winner based on the ages of the Best Actress winners over various years.

**Data:**

- **Best Actress Ages:** 27, 29, 28, 60, 30, 34, 46, 28, 60, 30, 42, 56
- **Best Actor Ages:** 44, 38, 38, 46, 51, 49, 58, 53, 59, 38, 46, 35

**Task:**

Find the best predicted age of the Best Actor winner given the age of the Best Actress winner for that year is 29 years. Determine if this predicted age is within 5 years of the actual Best Actor winner whose age was 38 years.

**Formulation:**

To accomplish this, we need to establish the equation of the regression line:

\[ \hat{y} = a + bx \]

- **\(a\)** = y-intercept (rounded to one decimal place)
- **\(b\)** = slope (rounded to three decimal places)

Once the regression equation is found, substitute the given age of the Best Actress (29 years) into the equation to calculate the predicted age of the Best Actor.

**Solution Steps:**

1. Calculate the y-intercept (\(a\)).
2. Calculate the slope (\(b\)) of the regression line using the given data.
3. Substitute \(x = 29\) into the regression equation to find the predicted age of the Best Actor.
4. Compare the predicted age with the actual age of 38 years to check if it falls within a 5-year range.

This problem provides an opportunity to apply statistical analysis techniques to real-world data and make informed predictions.
Transcribed Image Text:### Regression Analysis Problem In this exercise, you are tasked with finding the regression equation using the given data. The first variable is the predictor (\(x\)) variable. The goal is to predict the age of the Best Actor winner based on the ages of the Best Actress winners over various years. **Data:** - **Best Actress Ages:** 27, 29, 28, 60, 30, 34, 46, 28, 60, 30, 42, 56 - **Best Actor Ages:** 44, 38, 38, 46, 51, 49, 58, 53, 59, 38, 46, 35 **Task:** Find the best predicted age of the Best Actor winner given the age of the Best Actress winner for that year is 29 years. Determine if this predicted age is within 5 years of the actual Best Actor winner whose age was 38 years. **Formulation:** To accomplish this, we need to establish the equation of the regression line: \[ \hat{y} = a + bx \] - **\(a\)** = y-intercept (rounded to one decimal place) - **\(b\)** = slope (rounded to three decimal places) Once the regression equation is found, substitute the given age of the Best Actress (29 years) into the equation to calculate the predicted age of the Best Actor. **Solution Steps:** 1. Calculate the y-intercept (\(a\)). 2. Calculate the slope (\(b\)) of the regression line using the given data. 3. Substitute \(x = 29\) into the regression equation to find the predicted age of the Best Actor. 4. Compare the predicted age with the actual age of 38 years to check if it falls within a 5-year range. This problem provides an opportunity to apply statistical analysis techniques to real-world data and make informed predictions.
Expert Solution
Step 1

Calculate the following values:

x y (x - mean_x)2 (y - mean_y)2 (x - mean_x)*(y - mean_y)
27 44 132.250 5.063 25.875
29 38 90.250 68.063 78.375
28 38 110.250 68.063 86.625
60 46 462.250 0.063 -5.375
30 51 72.250 22.563 -40.375
34 49 20.250 7.563 -12.375
46 58 56.250 138.063 88.125
28 53 110.250 45.563 -70.875
60 39 462.250 52.563 -155.875
22 58 272.250 138.063 -193.875
42 46 12.250 0.063 -0.875
56 35 306.250 126.563 -196.875
SUM        
462 555 2107 672.25 -397.5
Mean        
38.500 46.250      
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