Find the regression equation, letting the diameter be the predictor (x) variable. Find the best predicted circumference of a marble with a diameter of 1.3 cm. How does the result compare to the actual circumference of 4.1 Use a significance level of 0.05. Baseball Basketball Golf Soccer Tennis Ping-Pong|Volleyball 4.4 22.1 6.9 13.8 69.4 21.7 O Critical Values of the Pearson Correlation Coefficient r 4.1 12.9 Diameter 7.3 23.6 74.1 21.2 Circumference 22.9 66.6 ]NOTE: To test Ho:p = 0 Jagainst H,: p#0, reject H, ]if the absolute value of r is greater than the critical Jvalue in the table. Click the icon to view the critical values of the Pearson correlation coefficient r. a= 0.01 0.990 0.959 0.917 0.875 0.834 to 798 a= 0.05 0.950 0.878 0.811 0.754 0.707 0.666 0.632 0.602 0.576 0.553 0.532 0.514 to 497 n 4 The regression equation is y =+x. (Round to five decimal places as needed.) 6 17 8 |0.798 0.765 0.735 0.708 0.684 0.661 10.641 19 10 11 12 13 14 15 Enter your answer in the edit fields and then click Check Answer. 16 Io 623

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Average

In mathematics, everyone must have heard the term average in one place or other. Almost all types of calculation require taking out an average. In everyday life, the term is used for denoting a certain amount that can be said to be a typical quantity for multiple people or objects. In other words, if a group of people possesses a certain object, then the average gives us an idea regarding the quantity of the object possessed by each person. However, this is solely based on mathematical calculation. It is important to note that most people will not strictly have the average value in a group.