Find the regression​ equation, letting overhead width be the predictor​ (x) variable. Find the best predicted weight of a seal if the overhead width measured from a photograph is 1.6 cm. Can the prediction be​ correct? What is wrong with predicting the weight in this​ case? Use a significance level of 0.05.   Overhead Width​ (cm) 7.9 8.1 9.2 9.4 7.1 7.6   Weight​ (kg) 145 183 222 203 133 159     LOADING... Click the icon to view the critical values of the Pearson correlation coefficient r. The regression equation is y=nothing+nothingx. ​(Round to one decimal place as​ needed.) The best predicted weight for an overhead width of 1.6 cm is nothing kg. ​(Round to one decimal place as​ needed.) Can the prediction be​ correct? What is wrong with predicting the weight in this​ case?     A. The prediction cannot be correct because there is not sufficient evidence of a linear correlation. The width in this case is beyond the scope of the available sample data.   B. The prediction cannot be correct because a negative weight does not make sense and because there is not sufficient evidence of a linear correlation.   C. The prediction cannot be correct because a negative weight does not make sense. The width in this case is beyond the scope of the available sample data.   D. The prediction can be correct. There is nothing wrong with predicting the weight in this case.

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6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
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Find the regression​ equation, letting overhead width be the predictor​ (x) variable. Find the best predicted weight of a seal if the overhead width measured from a photograph is
1.6
cm. Can the prediction be​ correct? What is wrong with predicting the weight in this​ case? Use a significance level of
0.05.
 
Overhead Width​ (cm)
7.9
8.1
9.2
9.4
7.1
7.6
 
Weight​ (kg)
145
183
222
203
133
159
 
 
LOADING...
Click the icon to view the critical values of the Pearson correlation coefficient r.
The regression equation is
y=nothing+nothingx.
​(Round to one decimal place as​ needed.)
The best predicted weight for an overhead width of
1.6
cm is
nothing
kg.
​(Round to one decimal place as​ needed.)
Can the prediction be​ correct? What is wrong with predicting the weight in this​ case?
 
 
A.
The prediction cannot be correct because there is not sufficient evidence of a linear correlation. The width in this case is beyond the scope of the available sample data.
 
B.
The prediction cannot be correct because a negative weight does not make sense and because there is not sufficient evidence of a linear correlation.
 
C.
The prediction cannot be correct because a negative weight does not make sense. The width in this case is beyond the scope of the available sample data.
 
D.
The prediction can be correct. There is nothing wrong with predicting the weight in this case.
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