Algebra and Trigonometry (6th Edition)
6th Edition
ISBN:9780134463216
Author:Robert F. Blitzer
Publisher:Robert F. Blitzer
ChapterP: Prerequisites: Fundamental Concepts Of Algebra
Section: Chapter Questions
Problem 1MCCP: In Exercises 1-25, simplify the given expression or perform the indicated operation (and simplify,...
Related questions
Question
Find the real solutions for 3m^3-24m^2-2m+16=0 using factoring by grouping.
Solve EXACTLY like the example attached. Be sure to show all steps.
![Find the solutions for 40r³ - 8r²-25r+ 5 = 0
√40-14./10
2/10
58
√5
√8 √8
√40
की
$4
40r²³-8√²) + (-25v+5) = 0
8r² (5r-1) - 5 (5-1) = 0
(5r-1)(8r²-5)=0
5r-1=0
+1 +1
56=1
r= 1/s
8r²5=0
+S +S
2-
√re
r = ± √
कि
t
r= + 140
8
8 = ± √io
8r² = §
²=5
${₁+√103
Print](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F9c8a70ea-fbe2-40d2-a3f9-af9ca4e1fac4%2Fd0ea9469-5794-494e-883c-59d3b1d654eb%2Fdp6kdho_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Find the solutions for 40r³ - 8r²-25r+ 5 = 0
√40-14./10
2/10
58
√5
√8 √8
√40
की
$4
40r²³-8√²) + (-25v+5) = 0
8r² (5r-1) - 5 (5-1) = 0
(5r-1)(8r²-5)=0
5r-1=0
+1 +1
56=1
r= 1/s
8r²5=0
+S +S
2-
√re
r = ± √
कि
t
r= + 140
8
8 = ± √io
8r² = §
²=5
${₁+√103
Print
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