Find the ratio of the output values that correspond to increases of 1 in the input value. (Note: Some authors call this a 1 - unit growth/decay factor.) 6- (-1, 4) 2+ 1 (0, 1) (1, 0.25) -2 -1 3 4 LO 3.

Algebra and Trigonometry (6th Edition)
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ChapterP: Prerequisites: Fundamental Concepts Of Algebra
Section: Chapter Questions
Problem 1MCCP: In Exercises 1-25, simplify the given expression or perform the indicated operation (and simplify,...
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The task is to find the **ratio of the output values** that correspond to increases of 1 in the input value. (Note: Some authors call this a 1-unit growth/decay factor.)

### Explanation of the Graph:

The graph is a curve plotted on a coordinate plane with labeled points and axes. 

- The horizontal axis is labeled as \( x \) and the vertical axis is unmarked but typically represents \( y \).
- The curve is shown descending from left to right.
- Several points are marked on the graph:
  - \( (-1, 4) \) at \( x = -1 \) with \( y = 4 \).
  - \( (0, 1) \) at \( x = 0 \) with \( y = 1 \).
  - \( (1, 0.25) \) at \( x = 1 \) with \( y = 0.25 \).

### Analyzing the Curve:

- The curve suggests an exponential decay, where as \( x \) increases, \( y \) decreases rapidly.
- The ratio of output values for a change in the input by 1 unit can be calculated between the marked points:
  - From \( x = -1 \) to \( x = 0 \): Ratio = \( \frac{y(0)}{y(-1)} = \frac{1}{4} \)
  - From \( x = 0 \) to \( x = 1 \): Ratio = \( \frac{y(1)}{y(0)} = \frac{0.25}{1} = 0.25 \)

This data suggests the graph represents an exponential function characterized by continuously halving for each increase in \( x \) by 1 unit.
Transcribed Image Text:The task is to find the **ratio of the output values** that correspond to increases of 1 in the input value. (Note: Some authors call this a 1-unit growth/decay factor.) ### Explanation of the Graph: The graph is a curve plotted on a coordinate plane with labeled points and axes. - The horizontal axis is labeled as \( x \) and the vertical axis is unmarked but typically represents \( y \). - The curve is shown descending from left to right. - Several points are marked on the graph: - \( (-1, 4) \) at \( x = -1 \) with \( y = 4 \). - \( (0, 1) \) at \( x = 0 \) with \( y = 1 \). - \( (1, 0.25) \) at \( x = 1 \) with \( y = 0.25 \). ### Analyzing the Curve: - The curve suggests an exponential decay, where as \( x \) increases, \( y \) decreases rapidly. - The ratio of output values for a change in the input by 1 unit can be calculated between the marked points: - From \( x = -1 \) to \( x = 0 \): Ratio = \( \frac{y(0)}{y(-1)} = \frac{1}{4} \) - From \( x = 0 \) to \( x = 1 \): Ratio = \( \frac{y(1)}{y(0)} = \frac{0.25}{1} = 0.25 \) This data suggests the graph represents an exponential function characterized by continuously halving for each increase in \( x \) by 1 unit.
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