Find the radius of convergence, R, of the Maclaurin series of the function. In(1 + x) R =

Calculus: Early Transcendentals
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Chapter1: Functions And Models
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**Find the radius of convergence, \( R \), of the Maclaurin series of the function:**

\[ \ln(1 + x) \]

\[ R = \ \_\_\_\_\_\_\_\_ \]

---

This prompt is asking for the calculation of the radius of convergence of the Maclaurin series for the natural logarithm function, \( \ln(1 + x) \).

In general, the function \( \ln(1 + x) \) has a Maclaurin series which is given by:

\[ \ln(1 + x) = x - \frac{x^2}{2} + \frac{x^3}{3} - \frac{x^4}{4} + \cdots \]

To find the radius of convergence, \( R \), one can use the formula for the radius of convergence of a power series:

\[ R = \frac{1}{\limsup_{n \to \infty} \left| \frac{a_{n+1}}{a_n} \right|} \]

For this series, \( R = 1 \), indicating that the series converges for \( |x| < 1 \).

This topic is crucial for understanding where a series representation of a function is valid, which is an important concept in calculus and analysis.
Transcribed Image Text:**Find the radius of convergence, \( R \), of the Maclaurin series of the function:** \[ \ln(1 + x) \] \[ R = \ \_\_\_\_\_\_\_\_ \] --- This prompt is asking for the calculation of the radius of convergence of the Maclaurin series for the natural logarithm function, \( \ln(1 + x) \). In general, the function \( \ln(1 + x) \) has a Maclaurin series which is given by: \[ \ln(1 + x) = x - \frac{x^2}{2} + \frac{x^3}{3} - \frac{x^4}{4} + \cdots \] To find the radius of convergence, \( R \), one can use the formula for the radius of convergence of a power series: \[ R = \frac{1}{\limsup_{n \to \infty} \left| \frac{a_{n+1}}{a_n} \right|} \] For this series, \( R = 1 \), indicating that the series converges for \( |x| < 1 \). This topic is crucial for understanding where a series representation of a function is valid, which is an important concept in calculus and analysis.
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