Find the radius of convergence of the power series. (-1)"x" Σn=08"

Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
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**Problem Statement:**

Find the radius of convergence of the power series.

**Mathematical Expression:**

\[
\sum_{n=0}^{\infty} \frac{(-1)^n x^n}{9^n}
\]

**Explanation:**

The given power series is:

\[
\sum_{n=0}^{\infty} \frac{(-1)^n x^n}{9^n} = \sum_{n=0}^{\infty} \left(\frac{(-1)x}{9}\right)^n
\]

In this series, each term is of the form:

\[
a_n = \left(\frac{(-1)x}{9}\right)^n
\]

This is similar in form to a geometric series \(\sum_{n=0}^{\infty} r^n\), where \(r = \frac{(-1)x}{9}\).

The radius of convergence \(R\) is determined by the condition \(|r| < 1\).

Thus, for convergence:

\[
\left|\frac{x}{9}\right| < 1
\]

\[
|x| < 9
\]

**Conclusion:**

The radius of convergence of the series is \(R = 9\).
Transcribed Image Text:**Problem Statement:** Find the radius of convergence of the power series. **Mathematical Expression:** \[ \sum_{n=0}^{\infty} \frac{(-1)^n x^n}{9^n} \] **Explanation:** The given power series is: \[ \sum_{n=0}^{\infty} \frac{(-1)^n x^n}{9^n} = \sum_{n=0}^{\infty} \left(\frac{(-1)x}{9}\right)^n \] In this series, each term is of the form: \[ a_n = \left(\frac{(-1)x}{9}\right)^n \] This is similar in form to a geometric series \(\sum_{n=0}^{\infty} r^n\), where \(r = \frac{(-1)x}{9}\). The radius of convergence \(R\) is determined by the condition \(|r| < 1\). Thus, for convergence: \[ \left|\frac{x}{9}\right| < 1 \] \[ |x| < 9 \] **Conclusion:** The radius of convergence of the series is \(R = 9\).
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