Find the quotient, and write it in rectangular form. 8( cos 480° + i sin 480°) 2 (cos 120° + i sin 120°) 8( cos 480° + i sin 480°) 2 ( cos 120° + i sin 120°) (Simplify your answer, including any radicals. Use integers or fractions for any numbers in the expression. Type your answer in the form a + bi.)

Trigonometry (11th Edition)
11th Edition
ISBN:9780134217437
Author:Margaret L. Lial, John Hornsby, David I. Schneider, Callie Daniels
Publisher:Margaret L. Lial, John Hornsby, David I. Schneider, Callie Daniels
Chapter1: Trigonometric Functions
Section: Chapter Questions
Problem 1RE: 1. Give the measures of the complement and the supplement of an angle measuring 35°.
Question
**Problem Statement:**

Find the quotient, and write it in rectangular form.

\[
\frac{8 \left( \cos 480^\circ + i \sin 480^\circ \right)}{2 \left( \cos 120^\circ + i \sin 120^\circ \right)}
\]

---

\[
\frac{8 \left( \cos 480^\circ + i \sin 480^\circ \right)}{2 \left( \cos 120^\circ + i \sin 120^\circ \right)} = \boxed{\phantom{\frac{1}{1}}}
\]

(Simplify your answer, including any radicals. Use integers or fractions for any numbers in the expression. Type your answer in the form \(a + bi\).)

**Explanation:**

The problem requires you to simplify the given complex fraction and convert the result to rectangular form, \(a + bi\), where \(a\) and \(b\) are real numbers. 

**Steps for solving:**

1. **Calculate \(\cos 480^\circ\) and \(\sin 480^\circ\):**

   - \(\cos 480^\circ = \cos(480^\circ - 360^\circ) = \cos 120^\circ = -\frac{1}{2}\)
   - \(\sin 480^\circ = \sin(480^\circ - 360^\circ) = \sin 120^\circ = \frac{\sqrt{3}}{2}\)

2. **Substitute these values into the numerator:**

   \[
   8 (\cos 480^\circ + i \sin 480^\circ) = 8 \left(-\frac{1}{2} + i \frac{\sqrt{3}}{2}\right) = 8 \left(-\frac{1}{2} + i \frac{\sqrt{3}}{2}\right) = -4 + 4i\sqrt{3}
   \]

3. **Calculate \(\cos 120^\circ\) and \(\sin 120^\circ\):**

   - \(\cos 120^\circ = -\frac{1}{2}\)
   - \(\sin 120^\circ = \frac{\sqrt{3}}{2}\)

4. **Substitute these values into the denominator:**

   \[
Transcribed Image Text:**Problem Statement:** Find the quotient, and write it in rectangular form. \[ \frac{8 \left( \cos 480^\circ + i \sin 480^\circ \right)}{2 \left( \cos 120^\circ + i \sin 120^\circ \right)} \] --- \[ \frac{8 \left( \cos 480^\circ + i \sin 480^\circ \right)}{2 \left( \cos 120^\circ + i \sin 120^\circ \right)} = \boxed{\phantom{\frac{1}{1}}} \] (Simplify your answer, including any radicals. Use integers or fractions for any numbers in the expression. Type your answer in the form \(a + bi\).) **Explanation:** The problem requires you to simplify the given complex fraction and convert the result to rectangular form, \(a + bi\), where \(a\) and \(b\) are real numbers. **Steps for solving:** 1. **Calculate \(\cos 480^\circ\) and \(\sin 480^\circ\):** - \(\cos 480^\circ = \cos(480^\circ - 360^\circ) = \cos 120^\circ = -\frac{1}{2}\) - \(\sin 480^\circ = \sin(480^\circ - 360^\circ) = \sin 120^\circ = \frac{\sqrt{3}}{2}\) 2. **Substitute these values into the numerator:** \[ 8 (\cos 480^\circ + i \sin 480^\circ) = 8 \left(-\frac{1}{2} + i \frac{\sqrt{3}}{2}\right) = 8 \left(-\frac{1}{2} + i \frac{\sqrt{3}}{2}\right) = -4 + 4i\sqrt{3} \] 3. **Calculate \(\cos 120^\circ\) and \(\sin 120^\circ\):** - \(\cos 120^\circ = -\frac{1}{2}\) - \(\sin 120^\circ = \frac{\sqrt{3}}{2}\) 4. **Substitute these values into the denominator:** \[
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