Find the quadratic function y = ax? + bx + c whose graph passes through the points (-1, 2), (1, 8), and (2,14). Use y ax? + bx + c. 2 = a(-1)² + b(-1) + c 8 = a·12 + b·1 + c 14 = a•22 + b.2 + c When x = -1, y = 2: = 8: When x = 2, y When x = 1, y = 14: Solving a - b + c = 2 a + b + c = 8 4a + 2b + c = 14, a = 1, b = 3, and c = 4. The quadratic function, y = ax + bx + c, is y = x² + 3x + 4.

Algebra and Trigonometry (6th Edition)
6th Edition
ISBN:9780134463216
Author:Robert F. Blitzer
Publisher:Robert F. Blitzer
ChapterP: Prerequisites: Fundamental Concepts Of Algebra
Section: Chapter Questions
Problem 1MCCP: In Exercises 1-25, simplify the given expression or perform the indicated operation (and simplify,...
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Find the quadratic function y = ax? + bx + c whose graph
passes through the points (-1, 2), (1, 8), and (2,14).
Use y
ax? + bx + c.
2 = a(-1)² + b(-1) + c
8 = a·12 + b·1 + c
14 = a•22 + b.2 + c
When x =
-1, y = 2:
= 8:
When x = 2, y
When x = 1, y
= 14:
Solving
a - b + c = 2
a + b + c = 8
4a + 2b + c = 14,
a = 1, b = 3, and c = 4. The quadratic function,
y = ax + bx + c, is y = x² + 3x + 4.
Transcribed Image Text:Find the quadratic function y = ax? + bx + c whose graph passes through the points (-1, 2), (1, 8), and (2,14). Use y ax? + bx + c. 2 = a(-1)² + b(-1) + c 8 = a·12 + b·1 + c 14 = a•22 + b.2 + c When x = -1, y = 2: = 8: When x = 2, y When x = 1, y = 14: Solving a - b + c = 2 a + b + c = 8 4a + 2b + c = 14, a = 1, b = 3, and c = 4. The quadratic function, y = ax + bx + c, is y = x² + 3x + 4.
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