Find the problem location for the following case to make the program able to run?
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- #include <iostream>using namespace std; class TurtleNode { public: TurtleNode(int babiesInit = 0, TurtleNode* nextLoc = nullptr); void InsertAfter(TurtleNode* nodeLoc); TurtleNode* GetNext(); void PrintNodeData(); private: int babiesVal; TurtleNode* nextNodePtr;}; TurtleNode::TurtleNode(int babiesInit, TurtleNode* nextLoc) { this->babiesVal = babiesInit; this->nextNodePtr = nextLoc;} void TurtleNode::InsertAfter(TurtleNode* nodeLoc) { TurtleNode* tmpNext = nullptr; tmpNext = this->nextNodePtr; this->nextNodePtr = nodeLoc; nodeLoc->nextNodePtr = tmpNext;} TurtleNode* TurtleNode::GetNext() { return this->nextNodePtr;} void TurtleNode::PrintNodeData() { cout << this->babiesVal << endl;} int main() { TurtleNode* headObj = nullptr; TurtleNode* firstTurtle = nullptr; TurtleNode* secondTurtle = nullptr; TurtleNode* currTurtle = nullptr; int babies1; int babies2; cin >> babies1; cin…dict1 = {(1,1,1):"red", (2,1,-1):"green", (0,-1,1):"red", (0,0,-2):"blue"}In this case, there are 2 red points, and their centroid is at ( (1+0)/2, (1-1)/2, (1+1)/2 ) = (0.5, 0, 1)Considering that in this example there is only one green and one blue point, they are representing the respective color's centroid. Hence, your function should return the following dictionary:{"red":(0.5,0.0,1.0), "green":(2.0,1.0,-1.0), "blue":(0.0,0.0,-2.0)}5. Given the following code AFIFOQueue aQue = new AFIFOQueue (10); AStack astack - new AStack (10); for (int i = 1; i <1e; i++) { aQue. Enqueue (i); } for (int i = 1; i <=5; i++) { astack. Push( aQue.Dequeue ()); } while(!astack . Empty ()) aQue. Enqueue (astack.Pop()); a. After the above code is executed, what is the content of the queue? (Fill in the content of aQue below) Indicate where the front and rear are located. b. What is the content of astack?
- Language is c++ Assignment 6 C: Minesweeper - Simplified. For many years, computers sold with the Windows operating system would contain a game called M inesweeper. The player would be presented with a grid, where they would have to click an empty part of the map. If they clicked on a hidden mine, the game would be instantly over. However, if they clicked a safe spot, a hint about nearby mines would be displayed and the player would click another spot. The goal would be to flag all the hidden mines without hitting one. (As an aside, many people did not know these rules and just clicked around randomly until they hit a mine)We will be developing a simplified version of this game. You will prompt the user for a grid size and then created a 2D array with equal width and height (C++ students: Check the Appendix for more information on how to do this). You will initialize the 2D char array with each element equallying a ‘?’ symbol. You will then randomly generate one “mine” value per…void traceMe(double x, double y) { double z; z = (pow(x, y)); cout « fixed « showpoint <« setprecision(2)<« x « ", " « y « ", " « z « endl; int main() double one=2, two=6; traceMe(two, one); 2.00 , 6,00 , 36.00 6.00 , 2.00 , 36.00 6.00 , 2,00 , 64.00 O 6.00, 2.00, 4,00//testcreature.cpp int main(){ cout << "\nCreating an Creature.\n"; Creature c; c.run(); cout << "\nCreating a Wizard.\n"; Wizard w; w.run(); w.hover(); Widget wdg; wdg.run(); wdg.click(); TextCreature txt; txt.run(); txt.moved(); return 0;}
- class Pt: def init_(self, x, y): self.x X P(3,4) self.y = y def _str__(self): x, y = self.x, self.y return f'P({x},{y})' True 18 # add coordinate-wise def add_(self, other): nx = 13 14 ny = 15 16 return 17 Pt(1, 1) b = Pt (2, 3) с %3D а + b d = b + Pt(5, 6) print (c) print ( isinstance (d, Pt)) print (d) %3Dinhinclude Rsing namespace std; int maxResult( ) int maxVal for (int i { for (int j = 0; j <= n 0; i <= n; i += a) i; j += b) %3D %3D float z = (float)(n (i + j)) / (float)(c); if (floor(z) { int x = int y ceil(z)) i / a; j/ b; maxVal = max(maxVal, x + y (int)z); return maxVal; } int main() { max cout << maxResult( ); return 0; 1 } Input Compilation failed due to fellowing ons main.cpp:7:23: error: 'n' was not declared in this scope 7| for (int i = 0; i <= n; i a) main.cpp:7:31: error: 'a was not declared in this scope for (int i = 0; i <= n; i t= a) %3D main.cpp:9:36: error: b' was not declared in this scope | 6 for (int j = 0; j <= n - i; j - b) %3D main.cpp:11:45: error: 'c was not declared in this scopeInteger userValue is read from input. Assume userValue is greater than 1000 and less than 99999. Assign tensDigit with userValue's tens place value. Ex: If the input is 15876, then the output is: The value in the tens place is: 7 2 3 public class ValueFinder { 4 5 6 7 8 9 10 11 12 13 GHE 14 15 16} public static void main(String[] args) { new Scanner(System.in); } Scanner scnr int userValue; int tensDigit; int tempVal; userValue = scnr.nextInt(); Your code goes here */ 11 System.out.println("The value in the tens place is: + tensDigit);
- // Application allows user to enter a series of words // and displays them in reverse order import java.util.*; public class DebugEight4 { publicstaticvoidmain(String[] args) { Scanner input =newScanner(System.in); int x =0, y; String array[] =newString[100]; String entry; finalString STOP =XXX; StringBuffer message =new StringBuffer("The words in reverse order are\n"); System.out.println("Enter any word\n" + "Enter + STOP + when you want to stop"); entry = input.next(); while(!(entry.equals(STOP))) { array[x] = entry; ++x; System.out.println("Enter another word\n" + "Enter "+STOP+" when you want to stop"); entry = input.next(); } for(y = x -1; y >0; ++y) { message.append(array[y]); message.append("\n"); } System.out.println(message) }Plot asap! ;public String cleanNumber(String phoneNumber) { int digit=0; String result = ""; String number= ""; for (int i = 0; i < phoneNumber.length(); i++) { char ch = phoneNumber.charAt(i); if (Character.isDigit(ch)) { number = number + ch; digit++; } } if(digit == 10) System.out.println("("+phoneNumber.substring(1,3)+")"+"-"+phoneNumber.substring(4,6)+phoneNumber.substring(7,10)); else result = "Error"; return result; }} Argument "(444) 999-1234" Actual (44)-) 99- "" Expected "(444) 999-1234" "4449991234" (44)-99234 "" "(444) 999-1234" "444.999.1234" (44)-99.12 "" "(444) 999-1234" What am doing wrong? How can I make the actual look like the expected? What do I have to change?