Find the probability that in a random sample of 349 Floridians, between 18.6% and 27.4% have earned a bachelor's degree. P(0.186 < p < 0.274)
Find the probability that in a random sample of 349 Floridians, between 18.6% and 27.4% have earned a bachelor's degree. P(0.186 < p < 0.274)
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
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#21 I just need help with part B for this question please. I circled it in red, thank you
![According to the U.S. Census Bureau, 25.1% of Floridians have earned a bachelor’s degree. Let \( \hat{p} \) be the proportion of people that have earned a bachelor’s degree in a random sample of 349 Floridians. Determine the following probabilities. Round solutions to four decimal places, if necessary:
- Find the probability that in a random sample of 349 Floridians, greater than 28.9% have earned a bachelor’s degree.
\[
P(\hat{p} > 0.289) = \text{[calculation needed]}
\]
- Find the probability that in a random sample of 349 Floridians, between 18.6% and 27.4% have earned a bachelor’s degree.
\[
P(0.186 \leq \hat{p} \leq 0.274) = \text{[calculation needed]}
\]](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fec7d0b78-7026-4f2e-9cd3-9f6affde891c%2Fb0a34f37-134f-437e-bbca-2dbe82fe6db3%2Fkircduu_processed.jpeg&w=3840&q=75)
Transcribed Image Text:According to the U.S. Census Bureau, 25.1% of Floridians have earned a bachelor’s degree. Let \( \hat{p} \) be the proportion of people that have earned a bachelor’s degree in a random sample of 349 Floridians. Determine the following probabilities. Round solutions to four decimal places, if necessary:
- Find the probability that in a random sample of 349 Floridians, greater than 28.9% have earned a bachelor’s degree.
\[
P(\hat{p} > 0.289) = \text{[calculation needed]}
\]
- Find the probability that in a random sample of 349 Floridians, between 18.6% and 27.4% have earned a bachelor’s degree.
\[
P(0.186 \leq \hat{p} \leq 0.274) = \text{[calculation needed]}
\]
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