Instructions: Use technology to find the following binomial probabilities.Round to the nearest thousandth.Find the probabilities for the values of n and \(pL_ when the conditions forthe binomial distribution are met.n = 145, p = 0.701. P(r = 100)2. P(r < 90) =3. P(r > 50) =

Given : Binomial distribution with

Answered: Find the probabilities for the values…

Find the probabilities for the values of n and \(p_ when the conditions for the binomial distribution are met. n = 145, p = 0.70 1. P(r = 100) = 2. P(r < 90) = 3. P(r 2 50) =

A First Course in Probability (10th Edition)

10th Edition

ISBN:9780134753119

Author:Sheldon Ross

Publisher:Sheldon Ross

Chapter1: Combinatorial Analysis

Section: Chapter Questions

Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...

See similar textbooks

Related questions

Q: Determine whether or not the distribution is a discrete probability distribution and select the…

A: x-5-3-1P(X=x)

Q: ore on last attempt: 0.5 out of 1 (parts: 0.17/0.17, 0/0.17, 0.17/0.17, 0.17/0.17, 0/0.17,…

A: Hello there! there are more than three subparts in the question. According to our policies we cannot…

Q: Suppose that the amount of time that students spend studying in the library in one sitting is…

A: Given that, Mean, mu= 43 Standard deviation, sigma= 20 X~ Normal(43,20) We know that, Z…

Q: The time to fly between America to Japan is uniformly distributed with a minimum of 120 minutes and…

A: Define Random Variable,X : Time taken to fly between America.Given that, X ~ Uniform(120,150)So, PDF…

Q: Using the formula for a Poisson Distribution, solve this problem The pancake house is popular and…

A: The Poisson distribution is popular for modeling the number of times an event occurs in an interval…

Q: CNNBC recently reported that the mean annual cost of auto insurance is 1045 dollars. Assume the…

A: Given: μ = 1045 σ = 275 n = 100 Let X denote single randomly selected value. Thus, X~N(μ = 1045, σ =…

Q: Suppose the time it takes Brian to eat an apple is uniformly distributed between 5 and 10 minutes.…

A: Solution: Note: Hello! As you have posted more than 3 sub parts, we are answering the first 3…

Q: Suppose that 29% of all people love cats more than dogs. Among 10 random people, what is the…

A: From the provided information, Sample size (n) = 10 29% of all people love cats more than dogs that…

Q: There are four runners on a team. The team time is the sum of the individual times for the four…

A: Given Information : There are four runners on a team. The team time is the sum of the individual…

Q: The mean of Binomial distribution is 3 and variance is-. Find P(1 s x < 6)

Q: In a family with 3 children, the probability that all the children are girls is approximately 0.125.…

A: = Sample size = 1000 = Probability of success = 0.125Here is the Mean standard deviation

Q: The bus to Union Station leaves every 30 minutes and is uniformly distributed. Find the probability…

A: The probability that a randomly chosen person arriving at a random time will walk between 10 and 15…

Q: A banker's average number of error transactions per month is considered to fit the Poisson's…

A: Let X be the number of error transactions per month

Q: Mean is 100, standard deviation is 15, IQ values are 100, 120, 88, 92, 65. What is probability in…

A: From the provided information, Mean (µ) = 100 Standard deviation (σ) = 15 X~N (100, 15) Here X be a…

Q: If electricity power failures occur in a particular industry according to Poisson distribution with…

A: The mean is 15 so m=15 The Poisson distribution is given by: PX=r=15re-15r!

Q: Suppose that there are 125 individuals of White oak in a forest.The reproductive rate (b) of the…

A: Given :125 individuals of White oak in a forest. The reproductive rate (b) of the trees is…

Q: 3. (Mathematical Excursions by Aufmann). A consumer testing agency has tested the strengths of 3…

A: Given that: Company Breaking points of 1/8 inch rope in pounds Trustworthy 122, 141, 151, 114,…

Q: for binomial distribution probability of getting failure in exam =0.20 sample size is 35 students in…

Q: CNNBC recently reported that the mean annual cost of auto insurance is 1035 dollars. Assume the…

A: Given Mean=1035 Standard deviation=250

Q: The probability of hitting a target is 1/6. What is the probability of hitting the target at most…

Q: CNNBC recently reported that the mean annual cost of auto insurance is 1009 dollars. Assume the…

Q: A company produces steel rods. The lengths of the steel rods are normally distributed with a mean of…

A: Solution: Let X be the lengths of the steel rods are normally distributed with a mean of 117.6 cm…

Q: The average number of miles (in thousands) that a car's tire will function before needing…

Q: Suppose that the amount of time that students spend studying in the library in one sitting is…

A: Solution: Let X be the amount of time that students spend studying in the library in one sitting.…

Q: Suppose that the amount of time that students spend studying in the library in one sitting is…

A: The amount of time that students pend studying in the library in one sitting is indicated by X. In…

Q: A random variable follows a binomial distribution with a probability of success equal to 0.62. For a…

A: Given data, p=0.62 n=7 standard deviation σ =?

Q: he average credit card debt for public school teacher is 14,975. If the debt is normally distributed…

A: Given, μ=14,975 σ=5,650

Q: The distribution of binomial variable (x) has the following p=0,3 and n=9 determine probability…

A: Given The data is as follows: X~Binn=9, p=0.3

Q: The graph of the standard deviation indicates that the tighter the probability distribution, the…

A: For the given statement, we need to answer if it is true or false.

Q: Suppose the average time it takes to complete is 60 minutes with a population standard deviation of…

A: Given that the average time it takes to complete is 60 minutes with a population standard deviation…

Q: An Office has a mean of 4 meetings per day, find the probability that in four weeks, there are two…

A: Solution:Step 1:Using Poisson DistributionPoisson Distribution ParametersThe mean number of meetings…

Q: • Homework 4.2: Suppose for the returns (last 24 months) of stock A are 5, 10, -4, 6, -10, 12, 8,…

A: Measures of Dispersion: The word dispersion is used to denote the degree of heterogeneity in the…

Q: For the binomial distribution with N equals 24 and P equals point 6 state whether or not it is…

A: When n * p and n * q are greater than 5, you can use the normal approximation to the binomial to…

Q: CNNBC recently reported that the mean annual cost of auto insurance is 958 dollars. Assume the…

A: Given - μ= 958 σ= 232 n= 58 To find I) P( X < 986) II) P( M < 986)…

Q: A binomial experiment consists of 800 trials. The probability of success for each trial is 05 What…

A: Given,n=800p=0.5mean(μ)=np=800×0.5=400standard deviation(σ)=np(1-p)σ=800×0.5×0.5=14.1421

Q: Daniel is 1000 meters from his home and decides to walk home. Every time he takes one step, he goes…

A: There are two possible outcomes that the person goes forward or backwards and each steps is…

Q: A company produces steel rods. The lengths of the steel rods are normally distributed with a mean of…

A: Formula : z = (x̄ - μₓ̄ )/σₓ̄

Q: The average number of miles (in thousands) that a car's tire will function before needing…

A: the PDF of normal distribution is = 1/σ * √2π * e ^ -(x-u)^2/ 2σ^2standard normal distribution is a…

Q: For discrete probability distribution x 0 1 2 3 4 5 6 7 f 0 k 2k 2k 3k k^2 2k^2 7k^2+k The mean…

A: The value of k is obtained below: Thus, the value of k is 1/10.

Concept explainers

Estimation

A new framework of data analysis where the new statistical methods are used for interpreting the results and analyzing the data is known as estimation in statistics.

Question

100%

Instructions: Use technology to find the following binomial probabilities.
Round to the nearest thousandth.
Find the probabilities for the values of n and \(pL_ when the conditions for
the binomial distribution are met.
n = 145, p = 0.70
1. P(r = 100)
2. P(r < 90) =
3. P(r > 50) =

Expert Solution

This question has been solved!

Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.

This is a popular solution!

SEE SOLUTION Check out a sample Q&A here

Step 1

VIEW

Step 2

VIEW

Trending now

This is a popular solution!

Step by step

Solved in 2 steps with 1 images

SEE SOLUTION Check out a sample Q&A here

Knowledge Booster

$Point Estimation, Limit Theorems, Approximations, and Bounds$

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, probability and related others by exploring similar questions and additional content below.

Similar questions

CNNBC recently reported that the mean annual cost of auto insurance is 1010 dollars. Assume the standard deviation is 266 dollars. You take a simple random sample of 78 auto insurance policies.Find the probability that a single randomly selected value is less than 972 dollars.P(X < 972) = Find the probability that a sample of size n=78n=78 is randomly selected with a mean less than 972 dollars.P(M < 972) = Enter your answers as numbers accurate to 4 decimal places.
According to Experian , the average credit score of and American adult is 719 and the standard deviation of all credit scores of American adults is 69. Determine the following probabilities. Round solutions to four decimal places , if necessary . Determine the probability that a randomly selected American adult has a credit score less than or equal to 699 P(x <= 699) = Determine the probability that a randomly selected American adult has a credit score between 706 and 907 . P(706 < x < 907) =
Suppose the scores of students on an exam are normally distributed with a mean of 376 and a standard deviation of 30. Then approximately 95% of the exam scores lie between the integers _ & _ such that the mean is half way between these two integers. I know the answers are 316 and 436. But I don't know how they got them. I cannot use excel and so I need help to solve this by hand. Thanks so much in advance!
A bus heading to university is always scheduled to arrive at a certain bus stop at 7:30am. The difference between the actual arrival time and 7:30am is normally distributed with mean 0 and standard deviation of 2 minutes.A student who always has a class at 8am decided to be at the bus stop at 7:28am in order to try to guarantee catching this bus. What is the probability that the student will catch the bus on any particular day?Probability = What is the probability that the student will catch the bus at least 4 times out of 5 days?Probability =
Central Limit Theorem: When the maximum SAT score was 2400, scores had a mean = 1518 and standard deviation = 325. Assuming the scores are normally distributed, determine the probability of a score exceeding 1600. If 81 SAT scores are randomly selected, find the probability that their mean score exceeds 1600.
CNNBC recently reported that the mean annual cost of auto insurance is 1031 dollars. Assume the standard deviation is 204 dollars. You take a simple random sample of 63 auto insurance policies.Find the probability that a single randomly selected value is less than 971 dollars.P(X < 971) = Find the probability that a sample of size n=63n=63 is randomly selected with a mean less than 971 dollars.P(M < 971) = Enter your answers as numbers accurate to 4 decimal places. Submit QuestionQuestion 13
please only do: if you can teach explain each
The average jail population in the US is 700500 if the distribution is normal in the standard deviation 45000 find the probability that only randomly selected day the gaol population is less than 650000
Suppose the length of the pregnancies of a certain animal are approximately normally distributed with mean =300 days and a standard deviation =26 days. The probability that the mean of a random sample of 15 pregnancies is less than 291 days is approximately what? (Round to 4 decimal points)
The smallest number which is considered a usual value for the Random Variable can be found by "Mean - 2*standard deviation". The largest number which is considered a usual value for the Random Variable can be found by "Mean + 2*standard deviation" If X is a binomial random variable, where there are 170 trials, and p = 0.875 find the smallest value that would be considered usual for X (write as a decimal).