Find the present value of a continuous stream of income over 5 years when the rate of income is constant at $33,000 per year and the interest rate is 8%.

Linear Algebra: A Modern Introduction
4th Edition
ISBN:9781285463247
Author:David Poole
Publisher:David Poole
Chapter6: Vector Spaces
Section6.7: Applications
Problem 16EQ
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### Present Value of Continuous Income Stream

In this exercise, we are tasked with finding the present value of a continuous stream of income over 5 years. The conditions given are:

- The rate of income is constant at $33,000 per year.
- The interest rate is 8%.

To determine the present value (PV) of this continuous income stream, the formula used is:

\[PV = \int_{0}^{T} R \cdot e^{-rt} \, dt\]

Where:
- \(R\) is the rate of income per year.
- \(r\) is the interest rate.
- \(T\) is the duration in years.
- \(t\) is the time variable.

Given:
- \(R = 33000 \text{ USD/year}\)
- \(r = 0.08\)
- \(T = 5 \text{ years}\)

Substituting these values into the formula, we get:

\[PV = \int_{0}^{5} 33000 \cdot e^{-0.08t} \, dt\]

To solve this integral:
1. Integrate the function \(\int e^{-0.08t} \, dt\).
2. Apply the limits from 0 to 5.

After evaluating the integral, the present value should be rounded to the nearest dollar as needed. 

**Note**: In an actual educational setting, students would be guided to solve this integral step-by-step either manually or using computational tools for exact evaluation.

**Result Placeholder**:
The present value is \( \$ \boxed{} \). 

**Instruction**: (Round to the nearest dollar as needed.)

This exercise helps students understand key financial concepts and the application of calculus in economic scenarios.
Transcribed Image Text:### Present Value of Continuous Income Stream In this exercise, we are tasked with finding the present value of a continuous stream of income over 5 years. The conditions given are: - The rate of income is constant at $33,000 per year. - The interest rate is 8%. To determine the present value (PV) of this continuous income stream, the formula used is: \[PV = \int_{0}^{T} R \cdot e^{-rt} \, dt\] Where: - \(R\) is the rate of income per year. - \(r\) is the interest rate. - \(T\) is the duration in years. - \(t\) is the time variable. Given: - \(R = 33000 \text{ USD/year}\) - \(r = 0.08\) - \(T = 5 \text{ years}\) Substituting these values into the formula, we get: \[PV = \int_{0}^{5} 33000 \cdot e^{-0.08t} \, dt\] To solve this integral: 1. Integrate the function \(\int e^{-0.08t} \, dt\). 2. Apply the limits from 0 to 5. After evaluating the integral, the present value should be rounded to the nearest dollar as needed. **Note**: In an actual educational setting, students would be guided to solve this integral step-by-step either manually or using computational tools for exact evaluation. **Result Placeholder**: The present value is \( \$ \boxed{} \). **Instruction**: (Round to the nearest dollar as needed.) This exercise helps students understand key financial concepts and the application of calculus in economic scenarios.
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