Find the position vector for a particle with acceleration, initial velocity, and initial position given below. ä(t) (5t, 2 sin(t), cos(2t)) v(0) = ( – 5, – 4, – 3) %3D F(0) = (0, – 4, – 3) F(t)
Find the position vector for a particle with acceleration, initial velocity, and initial position given below. ä(t) (5t, 2 sin(t), cos(2t)) v(0) = ( – 5, – 4, – 3) %3D F(0) = (0, – 4, – 3) F(t)
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Find the position vector for a particle with acceleration, initial velocity, and initial position given below.
→a(t)=⟨5t,2sin(t),cos(2t)⟩a→(t)=⟨5t,2sin(t),cos(2t)⟩
→v(0)=⟨−5,−4,−3⟩v→(0)=⟨-5,-4,-3⟩
→r(0)=⟨0,−4,−3⟩r→(0)=⟨0,-4,-3⟩
→r(t)=r→(t)= < , , >
< , , >
Transcribed Image Text:Find the position vector for a particle with acceleration, initial velocity, and initial position given
below.
a(t)
= (5t, 2 sin(t), cos(2t))
в(0) — (— 5, — 4, — 3)
т (0) — (0, — 4, — 3)
-
7(t)
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