Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
Related questions
Question
![Find the points at which the following polar curve has a horizontal or a vertical tangent line.
r=2 sin 20
At what points does the polar curve have a horizontal tangent line?
OA.
(0.2). (0.). (2,0,), and (±2,7 +0₁), where tan 0₁ = √/2
4√/2
4√2
+ 3-0₁, where tan 0₁ = √2
OB. (0,0), (0,r),
3x 4√2
O C.
1
(0.). (0.²). (+41² 0₁). and (+4+²,2-0,), where tand, = -√2
4√2)
(*
3
3-0₂
√√2
4√3
OD. (0,0), (0,r),
, and
and t
4√3
-0₁ , where tan 0₁ = √3
At what points does the polar curve have a vertical tangent line?
○ D. (0,0), (0,2), ( + 4√2,0₂), and (±
1
O A. (0,0), (0,), (±2,0₂), and (±2,x+0₂), where tan 8₂ =
√√2
4√2
4√2
1
OB.
t
--0₂
3
(0.5) - (0.-27). (+44² 0₂2). and (+44² 4-83). Where tan 02
and (2
- 4√³ x-₂):
O C.
(0.7), (0.37). (+ 4√³,0₂),
3
, where tan 0₂ =
4√/2
3-02, where tan 0₂ = √2
1
√√3](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F844281c0-c621-44a5-8564-9e61584c69dd%2Fdc0d0d73-2b3c-4d3a-95f7-db0f053fa03d%2Fp6vrmi_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Find the points at which the following polar curve has a horizontal or a vertical tangent line.
r=2 sin 20
At what points does the polar curve have a horizontal tangent line?
OA.
(0.2). (0.). (2,0,), and (±2,7 +0₁), where tan 0₁ = √/2
4√/2
4√2
+ 3-0₁, where tan 0₁ = √2
OB. (0,0), (0,r),
3x 4√2
O C.
1
(0.). (0.²). (+41² 0₁). and (+4+²,2-0,), where tand, = -√2
4√2)
(*
3
3-0₂
√√2
4√3
OD. (0,0), (0,r),
, and
and t
4√3
-0₁ , where tan 0₁ = √3
At what points does the polar curve have a vertical tangent line?
○ D. (0,0), (0,2), ( + 4√2,0₂), and (±
1
O A. (0,0), (0,), (±2,0₂), and (±2,x+0₂), where tan 8₂ =
√√2
4√2
4√2
1
OB.
t
--0₂
3
(0.5) - (0.-27). (+44² 0₂2). and (+44² 4-83). Where tan 02
and (2
- 4√³ x-₂):
O C.
(0.7), (0.37). (+ 4√³,0₂),
3
, where tan 0₂ =
4√/2
3-02, where tan 0₂ = √2
1
√√3
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