Find the point (x,y), at which the graph of y = 2x² + 3x-5 has a horizontal tangent. The function y = 2x² + 3x-5 has a horizontal tangent at (Type an ordered pair. Type simplified fractions.)
Find the point (x,y), at which the graph of y = 2x² + 3x-5 has a horizontal tangent. The function y = 2x² + 3x-5 has a horizontal tangent at (Type an ordered pair. Type simplified fractions.)
Holt Mcdougal Larson Pre-algebra: Student Edition 2012
1st Edition
ISBN:9780547587776
Author:HOLT MCDOUGAL
Publisher:HOLT MCDOUGAL
ChapterCSR: Contents Of Student Resources
Section: Chapter Questions
Problem 8.34EP
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Transcribed Image Text:Find the point (x,y), at which the graph of y = 2x² + 3x-5 has a horizontal tangent.
The function y = 2x² + 3x-5 has a horizontal tangent at
(Type an ordered pair. Type simplified fractions.)

Transcribed Image Text:ection 3.1-
S
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Find the point (x,y), at which the graph of y = 3x² + 4x-5 has a horizontal tangent.
f(x+h)-f(x)
The slope, m, of a curve y = f(x) at any point (x,y) is m = lim h
h→0
lim
h→0
f(x+h)-f(x)
h
6x + 4 = 0
x = -
= lim
2
Print
h→0
=
= 6x + 4
So, the slope, m, of the curve at any point (x,y) is m = 6x + 4.
The slope of a horizontal tangent is 0.
Solve for x.
3(x+h)² +
+4(x +h)-5-(3x² + 4x-5)
h
lim (6x +3h+4)
h→0
The point, (x,y), at which the tangent is horizontal is
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