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Find the point (x,y), at which the graph of y = 2x² + 3x-5 has a horizontal tangent. The function y = 2x² + 3x-5 has a horizontal tangent at (Type an ordered pair. Type simplified fractions.)

Find the point (x,y), at which the graph of y = 2x² + 3x-5 has a horizontal tangent. The function y = 2x² + 3x-5 has a horizontal tangent at (Type an ordered pair. Type simplified fractions.)

Glencoe Algebra 1, Student Edition, 9780079039897, 0079039898, 2018
Glencoe Algebra 1, Student Edition, 9780079039897, 0079039898, 2018
18th Edition
ISBN:9780079039897
Author:Carter
Publisher:Carter
Chapter9: Quadratic Functions And Equations
Section9.1: Graphing Quadratic Functions
Problem 38PPS
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Find the point (x,y), at which the graph of y = 2x² + 3x-5 has a horizontal tangent. The function y = 2x² + 3x-5 has a horizontal tangent at (Type an ordered pair. Type simplified fractions.)
Transcribed Image Text:Find the point (x,y), at which the graph of y = 2x² + 3x-5 has a horizontal tangent. The function y = 2x² + 3x-5 has a horizontal tangent at (Type an ordered pair. Type simplified fractions.)
ection 3.1- S View an example | All parts showing Find the point (x,y), at which the graph of y = 3x² + 4x-5 has a horizontal tangent. f(x+h)-f(x) The slope, m, of a curve y = f(x) at any point (x,y) is m = lim h h→0 lim h→0 f(x+h)-f(x) h 6x + 4 = 0 x = - = lim 2 Print h→0 = = 6x + 4 So, the slope, m, of the curve at any point (x,y) is m = 6x + 4. The slope of a horizontal tangent is 0. Solve for x. 3(x+h)² + +4(x +h)-5-(3x² + 4x-5) h lim (6x +3h+4) h→0 The point, (x,y), at which the tangent is horizontal is view ali ελαιιμιτ Get more neip ७० 2 19 3¹ HW Score: 90.91%. 10 of 11 Close Cical all X
Transcribed Image Text:ection 3.1- S View an example | All parts showing Find the point (x,y), at which the graph of y = 3x² + 4x-5 has a horizontal tangent. f(x+h)-f(x) The slope, m, of a curve y = f(x) at any point (x,y) is m = lim h h→0 lim h→0 f(x+h)-f(x) h 6x + 4 = 0 x = - = lim 2 Print h→0 = = 6x + 4 So, the slope, m, of the curve at any point (x,y) is m = 6x + 4. The slope of a horizontal tangent is 0. Solve for x. 3(x+h)² + +4(x +h)-5-(3x² + 4x-5) h lim (6x +3h+4) h→0 The point, (x,y), at which the tangent is horizontal is view ali ελαιιμιτ Get more neip ७० 2 19 3¹ HW Score: 90.91%. 10 of 11 Close Cical all X
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