Find the point P on the curve r(t) that lies closest to Po and state the distance between Po and P. r(t) = i+ 2tj + 2tk; Po(4,14,13) (? -4)2 + (2t – 14)2 + (2t – 13)2 Distance = If the distance is minimized, then the square of the distance is also minimized. To find the minimum distance, differentiate the square of the distance with respect to t and find the value of t for which the result is zero. The square of the distance is (P - 4)2 + (2t – 14)2 + (2t – 13)2. Differentiate this expression with respect to t. +(2t - 14)2 + (2t – 13)2] = 413 – 108 Now set the derivative equal to zero to find the value of t that minimizes the distance. 4t3 - 108 413 = 108 t = 3
Rate of Change
The relation between two quantities which displays how much greater one quantity is than another is called ratio.
Slope
The change in the vertical distances is known as the rise and the change in the horizontal distances is known as the run. So, the rise divided by run is nothing but a slope value. It is calculated with simple algebraic equations as:
I have attached a picture of my problem regarding finding the point on a curve r(t) that is closest to another given point off of the curve. I have used the distance formula using the equation and given point in the i, j, and k directions. Why is it that when the derivative square of the distance is set to zero, the distance is minimized(second included screenshot)?
Trending now
This is a popular solution!
Step by step
Solved in 3 steps with 3 images