Find the particular solution that satisfies the differential equation and the initial condition. f'(x) = 20x – 8x; f(1) = 1 f(x) =

Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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**Problem Statement:**

Find the particular solution that satisfies the differential equation and the initial condition.

\[
f'(x) = 20x^3 - 8x; \quad f(1) = 1
\]

**Find \( f(x) = \) (Box for solution)**

**Explanation:**

The problem requires finding a function \( f(x) \) such that its derivative with respect to \( x \) is equal to \( 20x^3 - 8x \), and it satisfies the initial condition \( f(1) = 1 \).

To solve this, integrate \( f'(x) = 20x^3 - 8x \) to find \( f(x) \), and use \( f(1) = 1 \) to determine the constant of integration.
Transcribed Image Text:**Problem Statement:** Find the particular solution that satisfies the differential equation and the initial condition. \[ f'(x) = 20x^3 - 8x; \quad f(1) = 1 \] **Find \( f(x) = \) (Box for solution)** **Explanation:** The problem requires finding a function \( f(x) \) such that its derivative with respect to \( x \) is equal to \( 20x^3 - 8x \), and it satisfies the initial condition \( f(1) = 1 \). To solve this, integrate \( f'(x) = 20x^3 - 8x \) to find \( f(x) \), and use \( f(1) = 1 \) to determine the constant of integration.
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Given that f'(x) = 20x3 - 8x and f(1) = 1 then find particular solution.

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