Find the parametric equations for the tangent line to the curve æ = t3 – 1,y = to +1, z = t° at the point (0, 2, 1). Use the variable t for your parameter. y =

Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
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**Problem Statement:**

Find the parametric equations for the tangent line to the curve 

\[ x = t^3 - 1, \, y = t^5 + 1, \, z = t^5 \]

at the point \((0, 2, 1)\). Use the variable \( t \) for your parameter.

**Blank Fields for Solutions:**

- \( x = \) [input field],
- \( y = \) [input field],
- \( z = \) [input field],

**Instructions:**

To find the parametric equations of the tangent line, follow these steps:

1. Determine the value of \( t \) at the given point by solving the system:
   - \( t^3 - 1 = 0 \),
   - \( t^5 + 1 = 2 \),
   - \( t^5 = 1 \).

2. Calculate the derivatives \(\frac{dx}{dt}\), \(\frac{dy}{dt}\), and \(\frac{dz}{dt}\) to find the tangent vector at the point.

3. Use the point and the tangent vector to write the parametric equations for the tangent line:
   - \( x(t) = x_0 + \frac{dx}{dt} \cdot (t - t_0) \),
   - \( y(t) = y_0 + \frac{dy}{dt} \cdot (t - t_0) \),
   - \( z(t) = z_0 + \frac{dz}{dt} \cdot (t - t_0) \), 

where \((x_0, y_0, z_0)\) is the given point and \((t_0)\) is the parameter corresponding to that point.
Transcribed Image Text:**Problem Statement:** Find the parametric equations for the tangent line to the curve \[ x = t^3 - 1, \, y = t^5 + 1, \, z = t^5 \] at the point \((0, 2, 1)\). Use the variable \( t \) for your parameter. **Blank Fields for Solutions:** - \( x = \) [input field], - \( y = \) [input field], - \( z = \) [input field], **Instructions:** To find the parametric equations of the tangent line, follow these steps: 1. Determine the value of \( t \) at the given point by solving the system: - \( t^3 - 1 = 0 \), - \( t^5 + 1 = 2 \), - \( t^5 = 1 \). 2. Calculate the derivatives \(\frac{dx}{dt}\), \(\frac{dy}{dt}\), and \(\frac{dz}{dt}\) to find the tangent vector at the point. 3. Use the point and the tangent vector to write the parametric equations for the tangent line: - \( x(t) = x_0 + \frac{dx}{dt} \cdot (t - t_0) \), - \( y(t) = y_0 + \frac{dy}{dt} \cdot (t - t_0) \), - \( z(t) = z_0 + \frac{dz}{dt} \cdot (t - t_0) \), where \((x_0, y_0, z_0)\) is the given point and \((t_0)\) is the parameter corresponding to that point.
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