Find the other five trigonometric ratios of 0. sin(0) = (No Response) cos(0) = (No Response) tan(0) csc(0) sec(0) = (No Response) = (No Response, |(No Response)

Calculus: Early Transcendentals
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ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Question-based on, "Find the other five trigonometric ratios".

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cot(0 with a line)=7/2

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**Find the other five trigonometric ratios of \( \theta \).**

- \( \sin(\theta) = \) (No Response)
- \( \cos(\theta) = \) (No Response)
- \( \tan(\theta) = \) (No Response)
- \( \csc(\theta) = \) (No Response)
- \( \sec(\theta) = \) (No Response)
Transcribed Image Text:**Find the other five trigonometric ratios of \( \theta \).** - \( \sin(\theta) = \) (No Response) - \( \cos(\theta) = \) (No Response) - \( \tan(\theta) = \) (No Response) - \( \csc(\theta) = \) (No Response) - \( \sec(\theta) = \) (No Response)
### Transcription for Educational Website

**Topic: Calculating the Hypotenuse of a Right Triangle**

The hypotenuse of a right triangle can be calculated using the Pythagorean theorem. Let's walk through the calculation:

1. **Formula**: 
   \[
   \text{hypotenuse} = \sqrt{2^2 + 7^2}
   \]

2. **Calculate Squared Values**:
   \[
   = \sqrt{4 + 49}
   \]

3. **Sum the Squares**:
   \[
   = \sqrt{53}
   \]

Therefore, the length of the hypotenuse is \(\sqrt{53}\).

**Diagram Explanation:**

- The diagram displays a right triangle with one angle labeled \(\theta\).
- The side opposite the right angle, or the hypotenuse, is labeled \(\sqrt{53}\).
- The other two sides are labeled as 2 and 7.

**Conclusion:**

The hypotenuse of this right triangle is \(\sqrt{53}\), matching the solution as indicated by "Option D."
Transcribed Image Text:### Transcription for Educational Website **Topic: Calculating the Hypotenuse of a Right Triangle** The hypotenuse of a right triangle can be calculated using the Pythagorean theorem. Let's walk through the calculation: 1. **Formula**: \[ \text{hypotenuse} = \sqrt{2^2 + 7^2} \] 2. **Calculate Squared Values**: \[ = \sqrt{4 + 49} \] 3. **Sum the Squares**: \[ = \sqrt{53} \] Therefore, the length of the hypotenuse is \(\sqrt{53}\). **Diagram Explanation:** - The diagram displays a right triangle with one angle labeled \(\theta\). - The side opposite the right angle, or the hypotenuse, is labeled \(\sqrt{53}\). - The other two sides are labeled as 2 and 7. **Conclusion:** The hypotenuse of this right triangle is \(\sqrt{53}\), matching the solution as indicated by "Option D."
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