Find the orthonormal basis of the subspace Y=lin([1,-2,-3,4,1], [4,3,-2,1,2],[1,-3,2,4,-3],[5,2,3,4,-5]) in the space X=R^5. Using basis Y to find the orthonormal basis of X.
Find the orthonormal basis of the subspace Y=lin([1,-2,-3,4,1], [4,3,-2,1,2],[1,-3,2,4,-3],[5,2,3,4,-5]) in the space X=R^5. Using basis Y to find the orthonormal basis of X.
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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Question
Find the orthonormal basis of the subspace Y=lin([1,-2,-3,4,1],
[4,3,-2,1,2],[1,-3,2,4,-3],[5,2,3,4,-5]) in the space X=R^5. Using basis Y to find the orthonormal basis of X.
use the information below
![Orthogonalization
€₁,..., en € (X, (, )) linearly independent vectors
fj+1(x₁,...,xj) = ||ej+1 = x₁e₁
-
= 0
afj+1(x1,...,xj)
8x1
fj+1(x1, j
მე
=
0
ofj+1(x1,...,xj) = 0
?хj
• ₁ = ||1||
ej+1
of linearly independent vectors
B =
=
= {e₁,...,en}, Â = {ê1,…..‚ên}.
— x¡¤¡||², j = 1, ..., N – 1
....
⇒ X1 = Xj+1,1,..., Xj = Xj+¹,j, j = 1,. N-1
e2 = €2x2,1€1;
e2 = €3x3,1€1 - x3,2€2
ēj+1
||ēj+1||'
ēj+1 = €j+1 −Xj+1,1€1 — Xj+1,2€2-... -
-
· — Xj+1,j¤j, j = 1, ..., N − 1](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Ff79bbcda-ba0d-4938-b53a-59a6b8504288%2F1b4fa4e5-2fc0-48ce-8af3-6026476c07a2%2F5hwkpwk_processed.png&w=3840&q=75)
Transcribed Image Text:Orthogonalization
€₁,..., en € (X, (, )) linearly independent vectors
fj+1(x₁,...,xj) = ||ej+1 = x₁e₁
-
= 0
afj+1(x1,...,xj)
8x1
fj+1(x1, j
მე
=
0
ofj+1(x1,...,xj) = 0
?хj
• ₁ = ||1||
ej+1
of linearly independent vectors
B =
=
= {e₁,...,en}, Â = {ê1,…..‚ên}.
— x¡¤¡||², j = 1, ..., N – 1
....
⇒ X1 = Xj+1,1,..., Xj = Xj+¹,j, j = 1,. N-1
e2 = €2x2,1€1;
e2 = €3x3,1€1 - x3,2€2
ēj+1
||ēj+1||'
ēj+1 = €j+1 −Xj+1,1€1 — Xj+1,2€2-... -
-
· — Xj+1,j¤j, j = 1, ..., N − 1
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