Find the optimal simplex tableau at the end of Phase I with row0 at the bottom for the following LP: Maximize z = 280 x1 + 40 x2+ 500 x3+510 x4 s.t. 30 x1 + 5 x2 + 45 x3 +60 x4≤ 5000 1 x1 + -5 x2 + 12 x3 +-10 x4> 1500 20 x1 + 8 x2 + 60 x3 +30 x4≤ 1800 0 x1 + 20 x2 + 0 x3 +120 x4≤ 5000 x1,x2,x3, x40 with w/ xl 15 0 0 0 0 1 -3 130 0 x2 x3 x4 75 -1 0 2 -3333 5 I 2 15 20 0 1 0 0 -16 81 ez 1 0 0 -1 1 2 120 0 0 0 0 0 -1 83 3314 - 1 5 1 60 84 0 0 0 00 0 1 0 0 0 1 0 0 0 RETA 3650 1140 30 5000 I

Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
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Find the optimal simplex tableau at the end of Phase I with row0 at the bottom
for the following LP:
Maximize z = 280 x1 + 40 x2+ 500 x3+510 x4
s.t.
30 x1 + 5 x2 + 45 x3 +60 x4≤ 5000
1 x1 + 5 x2 + 12 x3 +-10 x4> 1500
20 x1 + 8 x2 + 60 x3 +30 x4≤ 1800
0 x1 + 20 x2 + 0 x3 +120 x4≤ 5000
with x1,x2, x3, x40
wr xl
0
0
0
0
1
15
-3
1|1
0
x2 x3
T
-1 0
33
5
0
1
x4
75
2
0
-16 0 -1
2
15
20 0 120 0
1
81 ez
1 0
N|T
2
0
0
0
0
-1
83
3
4
1
-18
60
0
84 02
0 0
0 1
0
1
0
0
0 0
REJ
3650
1140
30
5000
||
Transcribed Image Text:Find the optimal simplex tableau at the end of Phase I with row0 at the bottom for the following LP: Maximize z = 280 x1 + 40 x2+ 500 x3+510 x4 s.t. 30 x1 + 5 x2 + 45 x3 +60 x4≤ 5000 1 x1 + 5 x2 + 12 x3 +-10 x4> 1500 20 x1 + 8 x2 + 60 x3 +30 x4≤ 1800 0 x1 + 20 x2 + 0 x3 +120 x4≤ 5000 with x1,x2, x3, x40 wr xl 0 0 0 0 1 15 -3 1|1 0 x2 x3 T -1 0 33 5 0 1 x4 75 2 0 -16 0 -1 2 15 20 0 120 0 1 81 ez 1 0 N|T 2 0 0 0 0 -1 83 3 4 1 -18 60 0 84 02 0 0 0 1 0 1 0 0 0 0 REJ 3650 1140 30 5000 ||
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