Find the nullspace of the system {4x1 – 2x2 (2x1 X1 + 2x2 – x3 – 4x4 + x5 + 2x6 = 0 + 3x5 – x6 = 0. + 5x6 = 0 - X3 + 2x4

Q: 7x+8dx X+3x+2

A:

Q: Evaluate (x-3)³dx x2

A: value = ?

Q: Solve the system +2₂ +5x3 11 4x₁ +5x₂ +213 = 5

A: Solution of given question is written in below steps.

Q: 2y-(4y+3)>6y+3(y+4)

A:

Q: X x² - 6x + 5 (-) 3x² - 2x - 2

A:

Q: 5x/ x2-x-12 - 2x-1 / x2-3x-4

A:

Q: Expand (3x + y). Expand (x1 + 2x2 + 3x3)*.

A: 1. 3x2+y52. x1+2x2+3x34

Q: -(4x5 - 3x3 + 5x - 2x2 + 2) - (-3x3

A: We have to simplify

Q: 3y2-2y-5

A: Solve for factor

Q: 1 х°— х5 +2х? — 3 dx -1

A: topic - definite integral note : As per bartleby guidelines, we are supposed to answer only first…

Q: x+2 xp- J +4x

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Q: write x2 + 3 as a linear combination of {x2 + 2x, x2 - 1, x + 2}, if possible.

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Q: (6a2b-2)-2/(2a-1b)-2

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Q: 3x+y=4 -x+y+5

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Q: 3y-5(3z-2y)-5z

A: This is from algebra... Expanding terms

Q: -11x+5-4(x-1)=-4x-(10x-4)+4

A:

Q: X1 X2 X3 -3X1 = - X2 + X3 = −6 5X3 2X1 + 4X2 - 2×2 + 3X3 X1 7.000 = = 50 = - X1 X2 X3 우 5

A:

Q: Find the LCD: S 3x x² + 8x + 15 x² + 3x-10 O (x+3)(x-1) O (x-3)(x+1) O (x-3)(x-2)(x+5) O…

A:

Q: 7x-2(3-2x) = 7x-2(3)-2(2x)  = 7x-6-4x = 3x-6

A: The expression 7x - 2(3-2x).

Q: (Vx +10xdx

A:

Q: -2x+9-y+13x-20+8x+z

A: Given: -2x+9-y+13x-20+8x+z

Q: X1 - 2x2 + X3 + X4 = 4 x1 + 2x2 + X3 + x4 = 1 2x1 = 5

A:

Q: J -dp- 2x² +3x + 1

A: