College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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![**Net Electric Flux Calculation**
To find the net electric flux through the blue surface, consider the following charge distributions:
- \( q_1 = +1.82 \, \text{nC} \) is outside the blue surface.
- Inside the blue surface:
- \( q_2 = +1.04 \, \text{nC} \)
- \( q_3 = -3.15 \, \text{nC} \)
**Diagram Explanation**
The visual representation includes three charges:
1. \( q_1 \) is depicted as a red point outside the blue spherical surface.
2. Within the blue sphere, two charges are present:
- \( q_2 \), a red point indicating a positive charge.
- \( q_3 \), a blue point indicating a negative charge.
**Flux Calculation**
According to Gauss's Law, the electric flux (\( \Phi \)) through a closed surface is given by:
\[
\Phi = \frac{{q_{\text{enclosed}}}}{\varepsilon_0}
\]
Where \( q_{\text{enclosed}} \) is the total charge enclosed by the surface, and \( \varepsilon_0 \) is the permittivity of free space.
Calculate \( q_{\text{enclosed}} \):
\[
q_{\text{enclosed}} = q_2 + q_3 = +1.04 \, \text{nC} - 3.15 \, \text{nC} = -2.11 \, \text{nC}
\]
Since \( q_1 \) is outside the blue surface, it does not contribute to \( q_{\text{enclosed}} \).
Substitute the value into Gauss's Law equation to find the net electric flux.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F0ec1abee-457f-4398-be04-96ed6fd65031%2F671e78c3-2ff8-4601-a531-32941e535341%2Fqtxjjcoy_processed.jpeg&w=3840&q=75)
Transcribed Image Text:**Net Electric Flux Calculation**
To find the net electric flux through the blue surface, consider the following charge distributions:
- \( q_1 = +1.82 \, \text{nC} \) is outside the blue surface.
- Inside the blue surface:
- \( q_2 = +1.04 \, \text{nC} \)
- \( q_3 = -3.15 \, \text{nC} \)
**Diagram Explanation**
The visual representation includes three charges:
1. \( q_1 \) is depicted as a red point outside the blue spherical surface.
2. Within the blue sphere, two charges are present:
- \( q_2 \), a red point indicating a positive charge.
- \( q_3 \), a blue point indicating a negative charge.
**Flux Calculation**
According to Gauss's Law, the electric flux (\( \Phi \)) through a closed surface is given by:
\[
\Phi = \frac{{q_{\text{enclosed}}}}{\varepsilon_0}
\]
Where \( q_{\text{enclosed}} \) is the total charge enclosed by the surface, and \( \varepsilon_0 \) is the permittivity of free space.
Calculate \( q_{\text{enclosed}} \):
\[
q_{\text{enclosed}} = q_2 + q_3 = +1.04 \, \text{nC} - 3.15 \, \text{nC} = -2.11 \, \text{nC}
\]
Since \( q_1 \) is outside the blue surface, it does not contribute to \( q_{\text{enclosed}} \).
Substitute the value into Gauss's Law equation to find the net electric flux.
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