Find the net capacitance (in pF) of the combination of series and parallel capacitors shown below. 2.0 µF 9.0 µF 5.5 µF 2.5 µF 0.55 µF 14 µF UF
Find the net capacitance (in pF) of the combination of series and parallel capacitors shown below. 2.0 µF 9.0 µF 5.5 µF 2.5 µF 0.55 µF 14 µF UF
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Transcribed Image Text:**Find the net capacitance (in µF) of the combination of series and parallel capacitors shown below.**
In the diagram, capacitors are arranged in both series and parallel configurations. The capacitances are labeled as follows:
- The first capacitor in series at the top left has a capacitance of 2.0 µF.
- The second capacitor in series directly below it has a capacitance of 9.0 µF.
- These are connected to a parallel branch consisting of two capacitors with capacitances of 5.5 µF and 2.5 µF.
- Further down, there is another series combination of capacitors with capacitances of 0.55 µF and 14 µF.
Below the diagram, there is an empty box followed by the unit “µF” where the calculated net capacitance should be entered.
To solve for the net capacitance:
1. Identify series and parallel groups.
2. Calculate equivalent capacitance for each group:
- For capacitors in series, use \( \frac{1}{C_{eq}} = \frac{1}{C_1} + \frac{1}{C_2} + \ldots \).
- For capacitors in parallel, use \( C_{eq} = C_1 + C_2 + \ldots \).
3. Combine the equivalents progressively to find the total capacitance.
Expert Solution
Step 1: Capacitor
Capacitor is an electrical component which stores electrical energy in a circuit. It is a passive component. Capacitors store energy in the form of an electric field. Capacitor consists of two metal plates separated by air or any other dielectric material.
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