FIND THE MOST PROBABLE VALUE OF THE ELEVATION OF A, B, AND C. ELEVATION OF A= 15.727 ELEVATION OF B = 18.850 ELEVATION OF C = 10.361 DIFFERENCE IN ELEVATION BETWEEN B AND A = 3.119 ( B above A) DIFFERENCE IN ELEVATION BETWEEN C AND C = 8.490 ( B above C) DIFFERENCE IN ELEVATION BETWEEN A AND C =5.369 ( A above C) SOLUTION: X = elevation of A X= 15.727 Y-X = 3.119 y = elevation of B Y = 18.850 Y-Z = 5.369 z = elevation of C Z = 10.361 X-Z = 5.369
FIND THE MOST PROBABLE VALUE OF THE ELEVATION OF A, B, AND C. ELEVATION OF A= 15.727 ELEVATION OF B = 18.850 ELEVATION OF C = 10.361 DIFFERENCE IN ELEVATION BETWEEN B AND A = 3.119 ( B above A) DIFFERENCE IN ELEVATION BETWEEN C AND C = 8.490 ( B above C) DIFFERENCE IN ELEVATION BETWEEN A AND C =5.369 ( A above C) SOLUTION: X = elevation of A X= 15.727 Y-X = 3.119 y = elevation of B Y = 18.850 Y-Z = 5.369 z = elevation of C Z = 10.361 X-Z = 5.369
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
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FIND THE MOST PROBABLE VALUE OF THE ELEVATION OF A, B, AND C. ELEVATION OF A= 15.727 ELEVATION OF B = 18.850 ELEVATION OF C = 10.361 DIFFERENCE IN ELEVATION BETWEEN B AND A = 3.119 ( B above A) DIFFERENCE IN ELEVATION BETWEEN C AND C = 8.490 ( B above C) DIFFERENCE IN ELEVATION BETWEEN A AND C =5.369 ( A above C) SOLUTION: X = elevation of A X= 15.727 Y-X = 3.119 y = elevation of B Y = 18.850 Y-Z = 5.369 z = elevation of C Z = 10.361 X-Z = 5.369 WRITE NORMAL EQUATIONS IN X, Y AND Z |
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