Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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![**Question:**
Find the most general antiderivative.
\[
\int (-8 \sec^2 x) \, dx
\]
**Options:**
- ( ) \(-8 \cot x + C\)
- ( ) \(8 \cot x + C\)
- ( ) \(\frac{\tan x}{8} + C\)
- ( ) \(-8 \tan x + C\)
In this problem, you're tasked with finding the antiderivative of \(-8 \sec^2 x\) with respect to \(x\). The antiderivative, also known as the indefinite integral, is a function that reverses the process of differentiation.
The expression \(\int (-8 \sec^2 x) \, dx\) suggests using the basic antiderivative of \(\sec^2 x\), which is \(\tan x\), scaled by the constant \(-8\). Thus, the correct answer involves recognizing this relationship and applying the constant of integration \(C\).](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F942000ab-5fd3-49a5-8751-6a899cd86937%2F55e15231-bcdb-4a71-8f91-6f8556c705c8%2F850j6l_processed.png&w=3840&q=75)
Transcribed Image Text:**Question:**
Find the most general antiderivative.
\[
\int (-8 \sec^2 x) \, dx
\]
**Options:**
- ( ) \(-8 \cot x + C\)
- ( ) \(8 \cot x + C\)
- ( ) \(\frac{\tan x}{8} + C\)
- ( ) \(-8 \tan x + C\)
In this problem, you're tasked with finding the antiderivative of \(-8 \sec^2 x\) with respect to \(x\). The antiderivative, also known as the indefinite integral, is a function that reverses the process of differentiation.
The expression \(\int (-8 \sec^2 x) \, dx\) suggests using the basic antiderivative of \(\sec^2 x\), which is \(\tan x\), scaled by the constant \(-8\). Thus, the correct answer involves recognizing this relationship and applying the constant of integration \(C\).
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