Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Question
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Find the molar conductivity according to these data and draw a graph.
![KCI (mol/dm^3) x(s/cm)
0.1
L(s).
K(1/cm)
1.
0.11173
0.118609 0.942
2.
0.01
0.01288
0.013586 0.948
3.
0.02
0.023156 0.024687 0.94
4.
0.001
0.001411 0.001486 0.949
K1=0.1117 s/cm / 0.118609 s = 0.942 1/cm
K2=0.01288 s/cm / 0.013586 s = 0.948 1/cm
K3=0.023156 s/cm / 0.023687 s = 0.937 ~0.940 1/cm
K4=0.001411 s/cm / 0.001486 s = 0.949 1/cm
Kl=K2=K3=K4=K](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fadc1a91a-8289-4c70-86d6-114dc2e56ef9%2F66f8f555-0b1f-425f-b1b5-0f84b207da8e%2F5tkw3n9_processed.jpeg&w=3840&q=75)
Transcribed Image Text:KCI (mol/dm^3) x(s/cm)
0.1
L(s).
K(1/cm)
1.
0.11173
0.118609 0.942
2.
0.01
0.01288
0.013586 0.948
3.
0.02
0.023156 0.024687 0.94
4.
0.001
0.001411 0.001486 0.949
K1=0.1117 s/cm / 0.118609 s = 0.942 1/cm
K2=0.01288 s/cm / 0.013586 s = 0.948 1/cm
K3=0.023156 s/cm / 0.023687 s = 0.937 ~0.940 1/cm
K4=0.001411 s/cm / 0.001486 s = 0.949 1/cm
Kl=K2=K3=K4=K
![M9SO4.7H2O(mol/dm^3)
L(s)
K(1/cm)
1.
0.2
0.030916
0.94
145.31
2.
0.1
0.01747
0.94
164.22
3.
0.05
0.009423
0.94
177.15
4.
0.025
0.004923
0.94
185.10
5.
0.0125
0.002567
0.94
193.04
^=1000KXL/C
^1= 1000x0.94x0.030916/0.2= 145.31
^2=1000x0.94x0.01747/0.1= 164.22
^3=1000x0.94x0.09423/0.05=177.15
^4=1000x0.94x0.04923/0.025=185.10
^5=1000x0.94x0.002567/0.0125=193.04](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fadc1a91a-8289-4c70-86d6-114dc2e56ef9%2F66f8f555-0b1f-425f-b1b5-0f84b207da8e%2Fmdp1ng_processed.jpeg&w=3840&q=75)
Transcribed Image Text:M9SO4.7H2O(mol/dm^3)
L(s)
K(1/cm)
1.
0.2
0.030916
0.94
145.31
2.
0.1
0.01747
0.94
164.22
3.
0.05
0.009423
0.94
177.15
4.
0.025
0.004923
0.94
185.10
5.
0.0125
0.002567
0.94
193.04
^=1000KXL/C
^1= 1000x0.94x0.030916/0.2= 145.31
^2=1000x0.94x0.01747/0.1= 164.22
^3=1000x0.94x0.09423/0.05=177.15
^4=1000x0.94x0.04923/0.025=185.10
^5=1000x0.94x0.002567/0.0125=193.04
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