Find the minimum distance from the point (6, 1, 6) to the plane x - y + z = 6. (Hint: To simplify the computations, minimize the square of the distance.)

Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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This question has several parts that must be completed sequentially. If you skip a part of the question, you will not receive any points for the
the skipped part.
Tutorial Exercise
Find the minimum distance from the point (6, 1, 6) to the plane x - y + z = 6. (Hint: To simplify the
computations, minimize the square of the distance.)
Step 1
Let (x, y, z) be a point in the plane x - y + z = 6. Substituting z in terms of x and y, this point is given by
(х, у, 2) %3D (х, у, 6 — | z
+ y).
Transcribed Image Text:This question has several parts that must be completed sequentially. If you skip a part of the question, you will not receive any points for the the skipped part. Tutorial Exercise Find the minimum distance from the point (6, 1, 6) to the plane x - y + z = 6. (Hint: To simplify the computations, minimize the square of the distance.) Step 1 Let (x, y, z) be a point in the plane x - y + z = 6. Substituting z in terms of x and y, this point is given by (х, у, 2) %3D (х, у, 6 — | z + y).
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