Find the minimum and the maximum of the function f(x, y) = x²+2x-2y on the set: D = {(x, y) : x² < y < 4, –2 < x < 2}

Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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I do not understand how to parameterize the function using critical points.

**Problem Statement:**

Determine the minimum and maximum values of the function \( f(x, y) = x^2 + 2x - 2y \) over the region defined by:

\[ D = \{ (x, y) : x^2 \leq y \leq 4, -2 \leq x \leq 2 \} \]

**Instructions:**

1. **Understand the Function:** The function \( f(x, y) \) is a quadratic in terms of \( x \) and linear in terms of \( y \).
   
2. **Analyze the Set \( D \):**
   - The inequality \( x^2 \leq y \) describes a region above the parabola \( y = x^2 \).
   - The inequality \( y \leq 4 \) restricts the region to lie below the line \( y = 4 \).
   - The boundaries for \( x \) are \(-2 \leq x \leq 2\), which means the region is also constrained horizontally between \( x = -2 \) and \( x = 2 \).

3. **Graphical Representation:**
   - To visualize the region \( D \), sketch the parabola \( y = x^2 \) and the horizontal line \( y = 4 \).
   - Shade the area that lies above the parabola and below the line.
   - The x-bounds \(-2\) and \(2\) create vertical lines that further narrow the shaded region.

4. **Finding Extrema:**
   - To find the extrema, you may evaluate the function at critical points within the region, as well as along the boundaries \( y = x^2 \) and \( y = 4 \).
   - Check endpoints and boundary intersections by substituting coordinates into \( f(x, y) \).

**Conclusion:**

Conclude by identifying the coordinates of points where the function attains its minimum and maximum values, specifying these values explicitly.
Transcribed Image Text:**Problem Statement:** Determine the minimum and maximum values of the function \( f(x, y) = x^2 + 2x - 2y \) over the region defined by: \[ D = \{ (x, y) : x^2 \leq y \leq 4, -2 \leq x \leq 2 \} \] **Instructions:** 1. **Understand the Function:** The function \( f(x, y) \) is a quadratic in terms of \( x \) and linear in terms of \( y \). 2. **Analyze the Set \( D \):** - The inequality \( x^2 \leq y \) describes a region above the parabola \( y = x^2 \). - The inequality \( y \leq 4 \) restricts the region to lie below the line \( y = 4 \). - The boundaries for \( x \) are \(-2 \leq x \leq 2\), which means the region is also constrained horizontally between \( x = -2 \) and \( x = 2 \). 3. **Graphical Representation:** - To visualize the region \( D \), sketch the parabola \( y = x^2 \) and the horizontal line \( y = 4 \). - Shade the area that lies above the parabola and below the line. - The x-bounds \(-2\) and \(2\) create vertical lines that further narrow the shaded region. 4. **Finding Extrema:** - To find the extrema, you may evaluate the function at critical points within the region, as well as along the boundaries \( y = x^2 \) and \( y = 4 \). - Check endpoints and boundary intersections by substituting coordinates into \( f(x, y) \). **Conclusion:** Conclude by identifying the coordinates of points where the function attains its minimum and maximum values, specifying these values explicitly.
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