Find the minimum and maximum values of the function y = 8/x² + 1 – 3x on the interval [0, 6] by comparing values at the critical points and endpoints. (Use decimal notation. Give your answers to three decimal places.) Ymin a Ymax =
Find the minimum and maximum values of the function y = 8/x² + 1 – 3x on the interval [0, 6] by comparing values at the critical points and endpoints. (Use decimal notation. Give your answers to three decimal places.) Ymin a Ymax =
College Algebra (MindTap Course List)
12th Edition
ISBN:9781305652231
Author:R. David Gustafson, Jeff Hughes
Publisher:R. David Gustafson, Jeff Hughes
Chapter3: Functions
Section3.CR: Chapter Review
Problem 89E
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Question
![Find the minimum and maximum values of the function y = 8/x² + 1 – 3x on the interval [0, 6] by comparing values at the
critical points and endpoints.
(Use decimal notation. Give your answers to three decimal places.)
Ymin =
Ymax 2](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F1ca2b2e2-412c-4f12-8bdf-9b458afbcb62%2F623ed633-6ef0-4e32-a63f-cd93a81a7b42%2F1r85qb4_processed.png&w=3840&q=75)
Transcribed Image Text:Find the minimum and maximum values of the function y = 8/x² + 1 – 3x on the interval [0, 6] by comparing values at the
critical points and endpoints.
(Use decimal notation. Give your answers to three decimal places.)
Ymin =
Ymax 2
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Step 1
Find maximum and minimum values of
y= 8√(x^2+1) -3x in interval [0,6]
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