Find the minimum and maximum values of the function y = 8/x² + 1 – 3x on the interval [0, 6] by comparing values at the critical points and endpoints. (Use decimal notation. Give your answers to three decimal places.) Ymin a Ymax =

College Algebra (MindTap Course List)
12th Edition
ISBN:9781305652231
Author:R. David Gustafson, Jeff Hughes
Publisher:R. David Gustafson, Jeff Hughes
Chapter3: Functions
Section3.CR: Chapter Review
Problem 89E
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Find the minimum and maximum values of the function y = 8/x² + 1 – 3x on the interval [0, 6] by comparing values at the
critical points and endpoints.
(Use decimal notation. Give your answers to three decimal places.)
Ymin =
Ymax 2
Transcribed Image Text:Find the minimum and maximum values of the function y = 8/x² + 1 – 3x on the interval [0, 6] by comparing values at the critical points and endpoints. (Use decimal notation. Give your answers to three decimal places.) Ymin = Ymax 2
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Find maximum and minimum values of 

y= 8√(x^2+1) -3x in interval [0,6] 

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