Find the median height.The frequency distribution table with the given cumulative frequencies becomes:Class intervalsFrequencyCumulative frequencyBelow 140140 - 14511145-150.1829150 - 15540155-1606.46160 - 165511 5125.5. This observation lies in the class 145 - 150. Then.Now n= 51. So.%3D22| (the lower limit) = 145.cf (the cumulative frequency of the class preceding 145 -150)= 11.f (the frequency of the median class 145 - 150) = 18.h (the class size) = 5.

Answered: Image /qna-images/answer/95efd0ca-b8db-451c-a543-06a23af7f419.jpg

Find the median height. The frequency distribution table with the given cumulative frequencies becomes: Class intervals Frequency Cumulative frequency Below 140 140 - 145 11 145-150. 18 29 40 150 - 155 155-160 46 160-165 51 = 25.5. This observation lies in the class 145-150. Then. 2. Now n=51. So. --- | (the lower limit) 145. cf (the cumulative frequency of the class preceding 145-150) 11. f (the frequency of the median class 145-150)= 18. h (the class size) = 5.

Find the median height. The frequency distribution table with the given cumulative frequencies becomes: Class intervals Frequency Cumulative frequency Below 140 140 - 145 11 145-150. 18 29 40 150 - 155 155-160 46 160-165 51 = 25.5. This observation lies in the class 145-150. Then. 2. Now n=51. So. --- | (the lower limit) 145. cf (the cumulative frequency of the class preceding 145-150) 11. f (the frequency of the median class 145-150)= 18. h (the class size) = 5.

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Question

Find the median height.
The frequency distribution table with the given cumulative frequencies becomes:
Class intervals
Frequency
Cumulative frequency
Below 140
140 - 145
11
145-150.
18
29
150 - 155
40
155-160
6.
46
160 - 165
51
1 51
25.5. This observation lies in the class 145 - 150. Then.
Now n= 51. So.
%3D
22
| (the lower limit) = 145.
cf (the cumulative frequency of the class preceding 145 -150)= 11.
f (the frequency of the median class 145 - 150) = 18.
h (the class size) = 5.

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