Find the measure of 4g if x || y, mzb x+ 15 and mzh 6x - 10. (Note: The diagram is not to scale.) А. 5 В. 20 С. 25 c/d D. 40 a /6 А B.

Algebra and Trigonometry (6th Edition)
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ChapterP: Prerequisites: Fundamental Concepts Of Algebra
Section: Chapter Questions
Problem 1MCCP: In Exercises 1-25, simplify the given expression or perform the indicated operation (and simplify,...
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### Problem Statement
Find the measure of ∠g if x ∥ y, \( m∠b = x + 15 \) and \( m∠h = 6x - 10 \).

(Note: The diagram is not to scale.)

### Options
- A. 5
- B. 20
- C. 25
- D. 40

### Diagram Explanation
The diagram features two parallel lines, labeled \( x \) and \( y \), that are intersected by a transversal line. The various angles created by the intersecting lines are labeled as follows:
- Upper left corner: ∠a
- Upper middle (adjacent to ∠a): ∠b
- Upper right corner: ∠c
- Middle right corner (adjacent to ∠c and vertically opposite to ∠g): ∠d
- Lower left corner (vertically opposite to ∠a and adjacent to ∠e): ∠e
- Lower middle (vertically opposite to ∠b): ∠f
- Lower right (vertically opposite to ∠c and adjacent to ∠h): ∠g
- Bottom right corner (adjacent to ∠g and ∠h): ∠h

### Multiple-Choice Answers
- O A
- O B
- O C
- O D

### Steps to Solution
1. Given \( x \parallel y \), we know that the alternate interior angles are congruent.
2. \( m∠b = x + 15 \) and \( m∠h = 6x - 10 \).
3. Since ∠b and ∠h are alternate interior angles, they are equal:
   \[ x + 15 = 6x - 10 \]
4. Solve for \( x \):
   \[ 15 + 10 = 6x - x \]
   \[ 25 = 5x \]
   \[ x = 5 \]
5. Substitute \( x \) back into the expression for \( m∠h \):
   \[ m∠h = 6(5) - 10 \]
   \[ m∠h = 30 - 10 \]
   \[ m∠h = 20 \]
6. Therefore, \( m∠g = m∠h = 20 \)
Transcribed Image Text:### Problem Statement Find the measure of ∠g if x ∥ y, \( m∠b = x + 15 \) and \( m∠h = 6x - 10 \). (Note: The diagram is not to scale.) ### Options - A. 5 - B. 20 - C. 25 - D. 40 ### Diagram Explanation The diagram features two parallel lines, labeled \( x \) and \( y \), that are intersected by a transversal line. The various angles created by the intersecting lines are labeled as follows: - Upper left corner: ∠a - Upper middle (adjacent to ∠a): ∠b - Upper right corner: ∠c - Middle right corner (adjacent to ∠c and vertically opposite to ∠g): ∠d - Lower left corner (vertically opposite to ∠a and adjacent to ∠e): ∠e - Lower middle (vertically opposite to ∠b): ∠f - Lower right (vertically opposite to ∠c and adjacent to ∠h): ∠g - Bottom right corner (adjacent to ∠g and ∠h): ∠h ### Multiple-Choice Answers - O A - O B - O C - O D ### Steps to Solution 1. Given \( x \parallel y \), we know that the alternate interior angles are congruent. 2. \( m∠b = x + 15 \) and \( m∠h = 6x - 10 \). 3. Since ∠b and ∠h are alternate interior angles, they are equal: \[ x + 15 = 6x - 10 \] 4. Solve for \( x \): \[ 15 + 10 = 6x - x \] \[ 25 = 5x \] \[ x = 5 \] 5. Substitute \( x \) back into the expression for \( m∠h \): \[ m∠h = 6(5) - 10 \] \[ m∠h = 30 - 10 \] \[ m∠h = 20 \] 6. Therefore, \( m∠g = m∠h = 20 \)
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